S4.10.3 Chapter 3

Waves on water

Priya's ripples run from deep water onto a shallow part of the tray. What happens to them?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

  • You picked D. Read on. At the end, the chapter comes back to your guess.

By the end you can

  • Measure the speed of ripples in a tray of water
  • Explain how water waves slow down and bend in shallow water

Drop a pebble into a pond and rings spread out from the place it fell. Each ring is a line of crests. Scientists study water waves in a shallow tray, seen from above, called a ripple tank.

Seen from above, a line that joins the crests is a wavefront. The wave travels at right angles to its fronts. A tap on the water makes circular wavefronts. A straight bar moved up and down makes straight ones.

Four circles round a dot, seen from above, each one the same distance outside the last. An arrow runs along a radius from the first circle to the second and is labelled wavelength.wavelength
Ripples from one tap. The rings are equally far apart. That gap is the wavelength.

The gap between two neighbouring rings, or two neighbouring straight fronts, is one wavelength. To measure it well, measure across several waves and divide. Do not measure a single gap, because the reading error is a bigger share of a small length.

A tray seen from above with five straight wavefronts, each the same distance from the next. An arrow above the tray runs from the first front to the last and is labelled 4 wavelengths. A label wavefront is under the first front. An arrow below the tray is labelled wave travels. The tray is labelled.tray4 wavelengthswavefrontwave travels
Five fronts have four gaps between them. Four gaps are four wavelengths.

Count the gaps, not the fronts. Five fronts leave four gaps, so the distance from the first front to the last is four wavelengths. A common slip is to divide by five.

To find the speed, use the wave equation from the last chapter: v = fλ. The frequency f is how many taps you make each second. The wavelength λ is the length you measure. Keep λ and v in the same length unit, such as cm and cm/s.

Worked example

Taps at 4 Hz make five fronts with 28 cm from the first to the last. Find the wavelength and the speed.

  1. Five fronts have four gaps. So four wavelengths together are 28 cm.
  2. One wavelength is λ = 28 cm ÷ 4 = 7 cm.
  3. The speed is v = fλ = 4 Hz × 7 cm = 28 cm/s.

Answer: 7 cm and 28 cm/s

Try it

Find the speed of ripples in a tray

You need: a flat tray or a wide dish, with water about 1.5 cm deep, a ruler, a pencil or a stick, a torch, a clock or phone that shows seconds, a phone camera to take a photo from above, if you have one.

Be safe: Keep the tray and the water away from sockets, wires and anything that runs on electricity. Wipe up spills at once, because a wet floor is slippery. Do not shine the torch into anyone's eyes.

  1. Put the tray on a table or the floor, on a dark cloth. Pour in water about 1.5 cm deep. Wait until the water is still.
  2. Lay the ruler flat on the edge of the tray where it shows along the water. Shine the torch low from the side, so the crests show as bright and dark lines.
  3. Tap the water with the tip of the pencil at one end, at a steady beat. Count your taps for 10 s and divide by 10. This is the frequency f in Hz. Try for about 4 taps each second.
  4. Look from straight above, or take a photo. Measure the distance across 5 fronts, which is 4 gaps. Divide by 4. This is the wavelength λ.
  5. Work out v = fλ.

What you will see: The ripples are a few centimetres apart and travel several tens of centimetres each second. Your numbers will differ with the depth of the water and how fast you tap. Measuring four gaps together is far better than measuring one.

If you cannot try it, this is what happens.
A table with the columns Measure and Value. Row 1: 40 taps in 10 s, f = 4 Hz. Row 2: 4 gaps, 32 cm. Row 3: wavelength, 8 cm. Row 4: speed 4 × 8, 32 cm/s.MeasureValue40 taps in 10 sf = 4 Hz4 gaps32 cmwavelength8 cmspeed 4 × 832 cm/s

Now change the depth. Once the water is shallower than about half a wavelength, water waves travel more slowly where it is shallower. Ripples in a tray 1.5 cm deep are in this range. This is also why ocean waves slow, shorten and rise as they reach a beach.

A tray of water seen from the side. The water is 1.5 cm deep at the left, marked with an arrow. At the right a plate lies on the bottom, shown with hatching and labelled plate, and the water over it is 0.5 cm deep, marked with an arrow. The water and the tray are labelled.1.5 cm0.5 cmwaterplatetray
A flat plate in the tray makes part of the water shallow.

Send straight ripples across the tray from the deep end to the plate. Here is what happens at the edge of the shallow part. The frequency does not change. The source makes the same number of waves each second, and the same number cross the edge each second.

The speed falls in the shallow water. The wave equation v = fλ then tells us the wavelength must fall too, because f stays the same. So the fronts bunch up in the shallow water. The new wavelength is λ = v ÷ f.

Next, let the ripples meet the edge at a slant. Each part of a front slows down as it reaches the shallow part. The part that arrives first slows first, so the front turns. It is like a cart whose wheel meets sand first and swings round.

To describe the turn, draw the normal: the line at 90° to the edge. The ripples travel along arrows at right angles to the fronts. In the slower, shallow water, the ripples turn towards the normal. This bending is refraction.

A square seen from above, split across the middle by an edge. The top half is deep water, labelled deep. The bottom half is shallow water, with dots, labelled shallow. Straight wavefronts slope across both halves. The fronts are further apart in the deep half and closer in the shallow half, and they meet the edge in the same places. A dashed line at right angles to the edge is labelled normal. Two thick arrows show the way the waves travel, one in each half. The one in the shallow half is closer to the normal. A short arrow between two fronts in each half is labelled λ.λλnormaldeepshallow
Ripples cross from deep to shallow water. The fronts are closer together, and the way they travel turns towards the normal. It is drawn with the speed ratio 0.6 of the worked example below. In a real tray the bend is often smaller, because the edge of the plate is not sharp.

Look at the edge. Every front that reaches the edge carries on into the shallow water without a break. So the fronts meet the edge equally far apart on both sides. That joining is why the direction must turn when the wavelength changes.

If the waves run from shallow water into deep water, they speed up and the wavelength grows. They then turn away from the normal. Along the normal itself, waves do not turn. Their wavelength and speed still change.

Worked example

In the deep part of a tray the wavelength is 5 cm. Ripples with a frequency of 4 Hz then cross to the shallow part, where the wavelength is 3 cm. Find the speed in each part.

  1. In the deep part v = fλ = 4 Hz × 5 cm = 20 cm/s.
  2. The frequency stays 4 Hz in the shallow part, because the source does not change.
  3. In the shallow part v = fλ = 4 Hz × 3 cm = 12 cm/s.

Answer: 20 cm/s and 12 cm/s

The ratio of the two speeds is 12 ÷ 20 = 0.6, which is the same as the ratio of the wavelengths, 3 ÷ 5. This works because the frequency is the same in both parts. The picture above is drawn with this ratio of 0.6.

Going further: the sea shows the same slowing on a huge scale. For a wave much longer than the water is deep, the speed is v = √(g × h). Here h is the depth in m, and g is 9.8 m/s². This rule is for tides and tsunamis. It is not for small ripples in a tray.

A table with the columns Sea depth and Speed. Row 1: 4 000 m, 198 m/s. Row 2: 100 m, 31 m/s. Row 3: 10 m, 10 m/s.Sea depthSpeed4 000 m198 m/s100 m31 m/s10 m10 m/s
The speed of a long wave in the sea. 198 m/s is about 710 km/h, nearly as fast as a jet airliner. The shallow sea near a coast slows it to about 36 km/h.

Worked example

A long wave crosses a sea that is 90 m deep. Find its speed.

  1. The rule for a long wave is v = √(g × h).
  2. Put in g = 9.8 m/s² and h = 90 m: g × h = 9.8 × 90 = 882.
  3. The square root is √882 = 29.7.
  4. So the speed is about 30 m/s.

Answer: About 30 m/s

As such a wave nears a coast, the water gets shallower and the wave slows. The energy the wave carries is squeezed into less water, so the wave grows taller. This is why a tsunami is small far out at sea and tall near the shore.

Try it

Ripples over a plate

You need: the tray and the water from before, about 1.5 cm deep, a flat tile or flat piece of board about 1 cm thick, with its top just under the surface, a pencil, a ruler and a torch.

Be safe: Keep the tray away from electrical things, and wipe up spills. Set the tile down gently, because it can crack the tray.

  1. Lay the tile flat at one end of the tray, so that the water over it is about 0.5 cm deep.
  2. Tap the water at the other end at a steady beat. Watch the ripples cross onto the tile.
  3. Look at how far apart the crests are over the tile compared with the deep part. Measure both, across four gaps.
  4. Try to tap so that the ripples meet the edge of the tile at a slant. Watch the way they turn.

What you will see: The crests are closer together over the tile. That is a shorter wavelength at the same frequency, so the waves are slower there. At a slant the ripples turn towards the normal on the tile. The effect is small, so look carefully, or take a photo from above.

If you cannot try it, this is what happens.
A table with the columns Part and Four gaps. Row 1: deep part, 24 cm. Row 2: over the tile, 17 cm.PartFour gapsdeep part24 cmover the tile17 cm
A tray seen from above with five straight wavefronts, each the same distance from the next. An arrow above the tray runs from the first front to the last and is labelled 20 cm. The tray is labelled, and an arrow below it is labelled wave travels.tray20 cmwave travels
Five fronts, with 20 cm across them. Count the gaps between them: one, two, three, four.

A wrong idea many people have

To find the wavelength, divide the distance across the fronts by the number of fronts.

Why it feels right: We count things to share a total. Five fronts look like five waves, so it seems right to divide by five.

The test that breaks it: Look at the picture: 20 cm across four gaps, not five. Divide 20 cm by 5 and you get 4 cm. The real gaps are 20 ÷ 4 = 5 cm.

What is true: Divide by the number of gaps, which is one less than the number of fronts. Six fronts have five gaps.

A wrong idea many people have

The frequency of ripples changes when they pass into shallow water.

Why it feels right: The ripples look different in the shallow part, with the crests closer together. It seems that the number of waves must have changed.

The test that breaks it: Count crests that pass a point in the deep part in 10 s, then in the shallow part in 10 s. The counts are the same. If one more arrived than left, the water at the edge would pile up forever.

What is true: The source sets the frequency, and it does not change when the wave crosses an edge. The speed and the wavelength change. The wavelength is v ÷ f.

A wrong idea many people have

Water waves speed up in shallow water.

Why it feels right: A wave on a beach seems to rush up the sand, and it looks fast as it breaks.

The test that breaks it: The ripples over the tile have crests closer together at the same frequency. With v = fλ, a smaller λ and the same f give a smaller v.

What is true: Waves slow down as the water gets shallower. A breaking wave looks quick because it is rising and tipping over, not because its speed has gone up.

Key words

ripple tank
a shallow tray of water, seen from above, for studying water waves.
wavefront
a line joining the crests of a wave, seen from above. The wave travels at right angles to it.
normal
a line at right angles (90°) to an edge, used to measure angles.
refraction
the turning of a wave when its speed changes at a slanted edge.

Back to your guess

The answer is A: Ripples slow down and bunch up as they run onto shallow water.

Water waves travel more slowly in shallower water. Their frequency stays the same, so the wavelength gets shorter and the crests bunch up. If they meet the shallow part at a slant, they also bend.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. The picture shows six wavefronts in a tray, with the distance across them. What is the wavelength?

    A tray seen from above with six straight wavefronts, each the same distance from the next. An arrow above the tray runs from the first front to the last and is labelled 30 cm. The tray is labelled.tray30 cm
    Tap your answer.
    1. Not this one. You divided 30 by 6, the number of fronts. Six fronts have only five gaps, and each gap is one wavelength. Try another.

    2. Yes, that is right. Six fronts have five gaps. Five wavelengths are 30 cm, so one wavelength is 30 ÷ 5 = 6 cm.

    3. Not this one. 30 cm is the distance across all five gaps. One wavelength is one gap. Try another.

    See the answer

    6 cm

    Six fronts have five gaps. Five wavelengths are 30 cm, so one wavelength is 30 ÷ 5 = 6 cm.

    • If you chose A: You divided 30 by 6, the number of fronts. Six fronts have only five gaps, and each gap is one wavelength.
    • If you chose C: 30 cm is the distance across all five gaps. One wavelength is one gap.
  2. Taps on water make 6 waves each second. The wavelength is 3 cm. How fast do the ripples travel?

    Tap your answer.
    1. Not this one. You added 6 and 3. The speed is the frequency times the wavelength. Try another.

    2. Not this one. You divided 6 by 3. The wave equation multiplies: v = fλ. Try another.

    3. Yes, that is right. v = fλ = 6 Hz × 3 cm = 18 cm/s.

    4. Not this one. You divided 3 by 6. Multiply the frequency and the wavelength instead. Try another.

    See the answer

    18 cm/s

    v = fλ = 6 Hz × 3 cm = 18 cm/s.

    • If you chose A: You added 6 and 3. The speed is the frequency times the wavelength.
    • If you chose B: You divided 6 by 3. The wave equation multiplies: v = fλ.
    • If you chose D: You divided 3 by 6. Multiply the frequency and the wavelength instead.
  3. Ripples run from deep water onto a plate where the water is shallow. What happens to their frequency?

    Tap your answer.
    1. Yes, that is right. The source sets the frequency. The same number of crests cross the edge every second, so the frequency is the same on both sides.

    2. Not this one. Closer crests mean a shorter wavelength, not a higher frequency. The same number of waves cross the edge each second. Try another.

    3. Not this one. The speed falls, but the frequency is set by the source. The same number of waves cross the edge each second. Try another.

    See the answer

    It stays the same.

    The source sets the frequency. The same number of crests cross the edge every second, so the frequency is the same on both sides.

    • If you chose B: Closer crests mean a shorter wavelength, not a higher frequency. The same number of waves cross the edge each second.
    • If you chose C: The speed falls, but the frequency is set by the source. The same number of waves cross the edge each second.
  4. Which statement describes ripples after they cross from deep water into shallow water?

    Tap your answer.
    1. Not this one. The wavelength does change, and the frequency does not. The source sets the frequency. Try another.

    2. Not this one. Shallow water slows waves. A longer wavelength would need a bigger speed at the same frequency. Try another.

    3. Not this one. With the same frequency, a shorter wavelength means a smaller speed. The speed does change. Try another.

    4. Yes, that is right. In shallow water the speed falls. The frequency is fixed by the source, so v = fλ gives a shorter wavelength.

    See the answer

    They go slower, with a shorter wavelength and the same frequency.

    In shallow water the speed falls. The frequency is fixed by the source, so v = fλ gives a shorter wavelength.

    • If you chose A: The wavelength does change, and the frequency does not. The source sets the frequency.
    • If you chose B: Shallow water slows waves. A longer wavelength would need a bigger speed at the same frequency.
    • If you chose C: With the same frequency, a shorter wavelength means a smaller speed. The speed does change.
  5. The picture shows a tray with a plate. Where do ripples travel slowest?

    A tray of water seen from the side. The water is 1.5 cm deep at the left, marked with an arrow. At the right a plate lies on the bottom, shown with hatching and labelled plate, and the water over it is 0.5 cm deep, marked with an arrow. The tray is labelled.1.5 cm0.5 cmplatetray
    Tap your answer.
    1. Not this one. There is more water to move, but that does not slow the wave. Waves travel faster in deeper water. Try another.

    2. Yes, that is right. Water waves slow down as the water gets shallower, so the ripples travel slowest over the plate.

    3. Not this one. The depth changes the speed. A wave over the plate is in less water and is slower. Try another.

    See the answer

    Over the plate, where the water is shallow.

    Water waves slow down as the water gets shallower, so the ripples travel slowest over the plate.

    • If you chose A: There is more water to move, but that does not slow the wave. Waves travel faster in deeper water.
    • If you chose C: The depth changes the speed. A wave over the plate is in less water and is slower.
  6. A long wave in the sea reaches the shore, where the water is shallow. What happens to its speed?

    Tap your answer.
    1. Yes, that is right. The speed of a long wave is √(g × h). As the depth h falls, the speed falls.

    2. Not this one. Nothing pushes the wave faster. Its speed follows the depth, and the depth falls near the shore. Try another.

    3. Not this one. The speed depends on the depth where the wave is now, not on where it began. Try another.

    4. Not this one. The source sets the frequency, and it does not change. The speed falls with the depth, and the wavelength gets shorter. Try another.

    See the answer

    It slows down.

    The speed of a long wave is √(g × h). As the depth h falls, the speed falls.

    • If you chose B: Nothing pushes the wave faster. Its speed follows the depth, and the depth falls near the shore.
    • If you chose C: The speed depends on the depth where the wave is now, not on where it began.
    • If you chose D: The source sets the frequency, and it does not change. The speed falls with the depth, and the wavelength gets shorter.
  7. Priya wants the speed of ripples in her tray. Which two measurements does she need?

    Tap your answer.
    1. Not this one. The amplitude, the height of the ripples, does not enter the wave equation. The speed needs the frequency and the wavelength. Go to S4.10.2. Try another.

    2. Yes, that is right. The wave equation v = fλ needs the frequency and the wavelength. She counts the taps to get f, and she measures across four gaps to get λ.

    3. Not this one. The amplitude does not enter the wave equation v = fλ. The wavelength is needed too. Go to S4.10.2. Try another.

    4. Not this one. The depth changes the speed, but it does not give the speed in this method. Use v = fλ. Go to S4.10.2. Try another.

    See the answer

    The frequency and the wavelength

    The wave equation v = fλ needs the frequency and the wavelength. She counts the taps to get f, and she measures across four gaps to get λ.

    • If you chose A: The amplitude, the height of the ripples, does not enter the wave equation. The speed needs the frequency and the wavelength. Go to S4.10.2.
    • If you chose C: The amplitude does not enter the wave equation v = fλ. The wavelength is needed too. Go to S4.10.2.
    • If you chose D: The depth changes the speed, but it does not give the speed in this method. Use v = fλ. Go to S4.10.2.
  8. From an earlier chapter

    A wave has a period of 0.5 s. What is its frequency?

    Tap your answer.
    1. Not this one. 0.5 is the period in seconds. The frequency is 1 divided by it. Go to S4.10.2. Try another.

    2. Not this one. You may have used 1 ÷ 0.05. The frequency is 1 ÷ 0.5. Go to S4.10.2. Try another.

    3. Yes, that is right. f = 1 ÷ T = 1 ÷ 0.5 = 2 Hz. Two waves pass each second.

    See the answer

    2 Hz

    f = 1 ÷ T = 1 ÷ 0.5 = 2 Hz. Two waves pass each second.

    • If you chose A: 0.5 is the period in seconds. The frequency is 1 divided by it. Go to S4.10.2.
    • If you chose B: You may have used 1 ÷ 0.05. The frequency is 1 ÷ 0.5. Go to S4.10.2.
  9. A long wave crosses a sea that is 600 m deep. Find its speed to the nearest whole m/s. Use g = 9.8 m/s².

    See the answer

    About 77 m/s

    v = √(g × h) = √(9.8 × 600) = √5 880 = 76.7, which is about 77 m/s.

  10. Ripples travel at 27 cm/s and their frequency is 3 Hz. What is the wavelength?

    See the answer

    9 cm

    λ = v ÷ f = 27 cm/s ÷ 3 Hz = 9 cm.

Keep it

Copy this into your exercise book.

v = fλ. Measure λ across several gaps: fronts − 1. Shallow water slows waves. f stays the same, so λ shortens and the wave bends towards the normal.

Draw: Straight wavefronts crossing an edge at a slant, closer together in the shallow part, with the normal and two arrows.

Reading with a child? A short page for the adult: what this chapter teaches and three questions to ask.

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