S4.10.5 Chapter 5

Reflection and refraction

A ray of light meets a mirror and makes an angle of 20° with its surface. At what angle was the ray arriving, in the way scientists measure it?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

By the end you can

  • Draw ray diagrams for reflection and refraction at a boundary
  • Explain total internal reflection and its use in optical fibres

Light travels in straight lines called rays. A ray is drawn as a straight line with an arrow that shows the way the light goes. This chapter follows rays when they meet a mirror, and when they meet the edge of glass or water.

Every angle is measured from the normal. The normal is a dashed line at 90° to the surface, drawn at the point where the ray meets it. The ray that arrives is the incident ray. The angle of incidence is the angle between the incident ray and the normal. The ray that leaves a mirror is the reflected ray. The angle of reflection is the angle between that ray and the normal.

A flat mirror drawn as a thick line, with hatching behind it, labelled mirror. A dashed line at right angles to the mirror is labelled normal. A ray labelled incident ray arrives from the upper left and meets the mirror at the foot of the normal. A ray labelled reflected ray leaves towards the upper right. The angle between each ray and the normal is marked 40°.mirrornormalincident rayreflected ray40°40°
The law of reflection: the angle of incidence equals the angle of reflection. Both are measured from the normal.

The law of reflection says two things. The angle of incidence equals the angle of reflection. And the incident ray, the normal and the reflected ray all lie in one flat plane. On a diagram, that plane is the page.

A very common slip is to measure the angle from the mirror, not from the normal. If a question says a ray makes 30° with the mirror, the angle of incidence is not 30°. It is 90° − 30° = 60°. Always draw the normal first.

The law holds for every ray on every surface. A rough surface, such as paper, is made of tiny patches that face different ways. Each ray obeys the law at its own patch, but the patches point in many directions, so the light scatters. A smooth mirror keeps parallel rays parallel, and you see an image.

Now look at your own image in a flat mirror. Rays from your face reflect from the mirror and reach your eye. Your eye follows each ray back in a straight line, to a point behind the mirror, where the image seems to be.

A flat mirror seen from the side, labelled mirror. An upright arrow in front of it is labelled object. A dashed arrow of the same height, the same distance behind the mirror, is labelled image. Two rays go from the tip and the foot of the object to the mirror and reflect to an eye on the left, labelled eye. Dotted lines go back behind the mirror from the mirror to the image. Marks under the picture show the distance from the object to the mirror and from the mirror to the image, both labelled 4 cm.objectimagemirroreye4 cm4 cm
The image is as far behind the mirror as the object is in front. The rays only seem to come from it.

The image in a flat mirror is the same size as the object. It is as far behind the mirror as the object is in front. It is upright. It is left and right reversed. It is a virtual image: light does not really pass through it, so you cannot catch it on a screen.

Now turn to refraction. Light travels at 3 × 10⁸ m/s in a vacuum and almost as fast in air. In glass and in water it is slower. The refractive index n of a material is the speed of light in a vacuum divided by the speed in the material.

A table with the columns Material, n and Speed. Row 1: air, 1.00, 3.0 × 10⁸. Row 2: water, 1.33, 2.26 × 10⁸. Row 3: glass, 1.5, 2.0 × 10⁸. Row 4: diamond, 2.42, 1.24 × 10⁸. The speeds are in metres a second.MaterialnSpeedair1.003.0 × 10⁸water1.332.26 × 10⁸glass1.52.0 × 10⁸diamond2.421.24 × 10⁸
Refractive index and the speed of light in m/s. Ordinary glass is about 1.5. Other kinds of glass differ a little.

When a ray goes into a material where light is slower, it bends towards the normal. When it goes into a material where light is faster, it bends away from the normal. A ray that travels along the normal does not bend, but it still changes speed.

A ray going from air into glass. The edge is a horizontal line, with the glass below it, shaded with dots and labelled glass, and the air above labelled air. A dashed line at right angles to the edge is labelled normal. The ray arrives from the upper left at 40° to the normal and bends towards the normal inside the glass, leaving at 25° to the normal.airglassnormal40°25°
Air to glass: the light slows down and bends towards the normal.
A ray going from glass into air. The edge is a horizontal line, with the glass below it, shaded with dots and labelled glass, and the air above labelled air. A dashed line at right angles to the edge is labelled normal. The ray rises from the lower left at 30° to the normal and bends away from the normal in the air, leaving at 49° to the normal.glassairnormal30°49°
Glass to air: the light speeds up and bends away from the normal.

How much does a ray bend? Snell's law gives the answer. For light going from air into a material of index n, sin i ÷ sin r = n. Here i is the angle of incidence and r is the angle of refraction, both from the normal. The sine of an angle is the ratio of two sides of a right angled triangle.

In general, light goes from a material of index n₁ into one of index n₂. Then n₁ × sin i = n₂ × sin r. In every case the ray bends towards the normal when n goes up, and away when n goes down.

A ray going from air into water. The edge is a horizontal line, with the water below it, shaded with dots and labelled water, and the air above labelled air. A dashed line at right angles to the edge is labelled normal. The ray arrives from the upper left and bends towards the normal in the water.airwaternormal
A ray enters water at 45° to the normal.

Worked example

A ray goes from air into water, whose refractive index is 1.33. The angle of incidence is 45°. Find the angle of refraction.

  1. Use sin i ÷ sin r = n, so sin r = sin i ÷ n.
  2. sin 45° = 0.7071, so sin r = 0.7071 ÷ 1.33 = 0.5317.
  3. The angle whose sine is 0.5317 is r = 32.1°.

Answer: 32.1°

A rectangular block of glass shows both bends. The ray bends towards the normal as it goes in, and away from the normal as it comes out. The two bends are equal and opposite, so the ray that leaves is parallel to the ray that went in. It is moved sideways.

A ray crossing a rectangular block of glass, labelled glass. The ray arrives from the upper left at 40° to the normal, marked 40°, and bends towards the normal inside the block at 25°, marked 25°. It leaves at the bottom parallel to the first ray but moved to one side. A dotted line shows the straight on path, labelled straight on. Two dashed normals are labelled normal.glassnormalstraight on40°25°
Through a glass block, the ray leaves parallel to the way it came in. It is at 40° to the normal again, but shifted sideways.

Now go the other way. A ray inside glass or water meets the edge with air. It bends away from the normal. As the angle of incidence grows, the bent ray swings closer to the edge. At one angle it runs along the edge. That angle is the critical angle, c.

At the critical angle, the angle of refraction is 90°. So sin c = 1 ÷ n for light going from a material of index n into air. For glass of index 1.5, c is about 42°.

Past the critical angle, no light can leave. All of it is reflected back inside, by the law of reflection. This is total internal reflection.

Three rays of light inside glass, all meeting the top edge at the same point, with air above. The glass is below the edge, shaded with dots and labelled glass. The air is labelled air. A dashed normal is labelled normal. The ray at the smallest angle bends away from the normal and leaves into the air, labelled bends out. The ray at the middle angle, the critical angle, runs along the edge, labelled along edge. The ray at the largest angle reflects back into the glass, labelled reflected.glassairnormalbends outalong edgereflected
Three rays in glass. Under the critical angle the light goes out. At it, the light runs along the edge. Beyond it, all the light is reflected.

Total internal reflection has two conditions. The light must go from a higher n to a lower n, such as glass to air. And the angle of incidence must be greater than the critical angle. Light going from air into glass can never be totally reflected.

Even when light does cross an edge, a little of it is also reflected. The diagrams leave that weak reflection out. Total internal reflection is different: there, all the light is reflected.

A ray inside water meeting the edge with air above. The water is below the edge, shaded with dots and labelled water. The air is labelled air. A dashed normal is labelled normal. The ray rises from the lower left at a large angle to the normal and is reflected back down into the water at the same angle.waterairnormal
A ray in water at 60° to the normal is past the critical angle. All of it is reflected.

Worked example

Water has a refractive index of 1.33. What is the critical angle for light going from water into air?

  1. At the critical angle, sin c = 1 ÷ n.
  2. sin c = 1 ÷ 1.33 = 0.7519.
  3. The angle whose sine is 0.7519 is c = 48.8°.

Answer: 48.8°

Diamond has a very high index. Its critical angle is small, so light that enters a cut diamond is reflected inside again and again before it comes out. This is part of why diamonds sparkle.

An optical fibre is a thin, flexible thread of glass. Light that enters one end meets the wall at an angle greater than the critical angle. It is totally reflected, again and again, and follows the fibre round bends to the far end.

A glass fibre that runs straight and then bends upwards, shaded with dots and labelled glass fibre. A ray of light labelled light enters at the left end. It zigzags along the fibre, reflecting from the walls, and follows the bend to the top end.glass fibrelight
A ray follows a bent fibre by total internal reflection. Every meeting with the wall is past the critical angle.

A real fibre has a core of glass inside a coating of glass of slightly lower index. The total internal reflection happens where the core meets the coating. A fibre cannot be bent too sharply. The light would then meet the wall at less than the critical angle and leak out.

Fibres carry telephone calls and the internet as pulses of light, which you meet in the last chapter. Doctors also use bundles of fibres in a thin tube, an endoscope, to look inside the body without a large cut.

Try it

Test the law of reflection

You need: a small flat mirror, a torch, two cards held with a narrow gap between them, a sheet of white paper, a pencil and a ruler, something to hold the mirror upright, such as a lump of clay or a book.

Be safe: Never shine the torch into anyone's eyes, and never use the Sun or a mirror in sunlight for this. Tape the edges of a glass mirror, which can cut. Keep the mirror and the clay away from young children.

  1. Draw a straight line across the paper. Stand the mirror upright on the line, with its shiny face towards you. Draw a dashed line at right angles to the mirror, as the normal. Mark where it meets the mirror.
  2. Lay the torch behind the two cards. A thin beam should come through the gap. It should cross the paper at a slant and meet the mirror at the foot of the normal. Keep the beam low and flat on the paper.
  3. Mark two small dots on the beam that goes to the mirror, and two on the beam that leaves it. Take away the mirror and the torch, and draw lines through the dots.
  4. Mark a point on each line exactly 10 cm from the mirror point. Measure how far each of the two points is from the normal.
  5. If the two distances are equal, the two angles are equal.

What you will see: The two distances come out almost the same, within a millimetre or so. A point 10 cm along a ray is 10 cm times the sine of the angle away from the normal. So equal distances mean equal angles.

If you cannot try it, this is what happens.
A table with the columns Point and Distance from normal. Row 1: on the incident ray, 6.1 cm. Row 2: on the reflected ray, 6.0 cm.PointFrom normalincident ray6.1 cmreflected ray6.0 cm

Try it

The silver surface of water

You need: a clear glass or jar, filled with water, a table.

Be safe: Use a glass or jar that cannot tip over, away from the edge of the table. If you have a clear plastic cup, use that. Wipe up any spills.

  1. Stand the glass of water on a table, away from the edge.
  2. Crouch so that your eye is a little lower than the top of the water. Look up at the underside of the water surface, through the side of the glass.
  3. Look steeply upwards. Then look at a slant, nearly along the underside of the surface.

What you will see: Looking steeply up, you see through the surface to the ceiling. At a shallow slant, the surface looks like a silver mirror. You see the bottom of the glass or the objects in the water. This is total internal reflection.

If you cannot try it, this is what happens.
A table with the columns Look and You see. Row 1: steeply up, through it. Row 2: at a slant, a mirror.LookYou seesteeply upthrough itat a slanta mirror

A wrong idea many people have

A ray that makes 30° with a mirror has an angle of incidence of 30°.

Why it feels right: The angle you can see is the one between the ray and the mirror. It is the first angle we think to measure on a flat surface.

The test that breaks it: Draw the normal first. The ray makes 30° with the mirror, and the mirror makes 90° with the normal. So the ray makes 90° − 30° = 60° with the normal. The law of reflection uses the angle from the normal.

What is true: Angles of incidence, reflection and refraction are always measured from the normal, never from the surface.

A wrong idea many people have

Light always bends towards the normal when it changes material.

Why it feels right: Our first picture of refraction is a ray going into water or glass, and that ray bends towards the normal.

The test that breaks it: Look at the ray going from glass into air. It bends away from the normal, and the angle in the air is bigger than the angle in the glass.

What is true: A ray bends towards the normal when it goes into a material where light is slower. It bends away from the normal when it goes into a material where light is faster.

A wrong idea many people have

Total internal reflection can happen when light goes from air into glass, if the angle is large enough.

Why it feels right: A large angle seems to be all it takes, and light reflects from a glass window at a slant.

The test that breaks it: From air into glass, sin r = sin i ÷ 1.5. This is always less than 1, so a refracted ray always exists. A window at a slant also reflects a little, but some light always goes in.

What is true: Total internal reflection needs two things. The light goes from a higher index to a lower index. The angle of incidence is greater than the critical angle.

Key words

angle of incidence
the angle between the incident ray and the normal.
angle of reflection
the angle between the reflected ray and the normal.
virtual image
an image made where rays seem to come from, so it cannot be caught on a screen.
refractive index
the speed of light in a vacuum divided by its speed in the material. It is written n.
critical angle
the angle of incidence in a denser material at which the refracted ray runs along the edge. sin c = 1 ÷ n.
total internal reflection
all the light reflected inside a material, when it meets the edge beyond the critical angle.
optical fibre
a thin glass thread that carries light along it by total internal reflection.

Back to your guess

The answer is B: 70°, because scientists measure from the line at right angles to the mirror.

Scientists measure the angle from the normal, the line at 90° to the mirror. A ray that makes 20° with the surface makes 90° − 20° = 70° with the normal. That is the angle of incidence.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. A ray of light makes an angle of 35° with the surface of a flat mirror. What is the angle of incidence?

    Tap your answer.
    1. Not this one. That is the angle with the mirror. The angle of incidence is measured from the normal, which is at 90° to the mirror. Try another.

    2. Not this one. You added 35° to 90°. Take it away instead: 90° − 35°. Try another.

    3. Yes, that is right. The normal is at 90° to the mirror. So the angle from the normal is 90° − 35° = 55°.

    See the answer

    55°

    The normal is at 90° to the mirror. So the angle from the normal is 90° − 35° = 55°.

    • If you chose A: That is the angle with the mirror. The angle of incidence is measured from the normal, which is at 90° to the mirror.
    • If you chose B: You added 35° to 90°. Take it away instead: 90° − 35°.
  2. An object stands 5 cm in front of a flat mirror, as in the picture. How far is the image from the object?

    A flat mirror seen from the side, labelled mirror. An upright arrow in front of it is labelled object. A dashed arrow behind the mirror is labelled image. Two rays go from the object to the mirror and reflect to an eye on the left, labelled eye. A mark under the picture from the object to the mirror is labelled 5 cm.objectimagemirroreye5 cm
    Tap your answer.
    1. Not this one. That is the distance from the object to the mirror. The image is also 5 cm behind the mirror, so the object and the image are further apart. Try another.

    2. Not this one. The image is not halfway. It is as far behind the mirror as the object is in front. Try another.

    3. Not this one. The image is as far behind the mirror as the object is in front, which is 5 cm, not 10 cm. Try another.

    4. Yes, that is right. The image is 5 cm behind the mirror, and the object is 5 cm in front of it. The distance between them is 5 + 5 = 10 cm.

    See the answer

    10 cm

    The image is 5 cm behind the mirror, and the object is 5 cm in front of it. The distance between them is 5 + 5 = 10 cm.

    • If you chose A: That is the distance from the object to the mirror. The image is also 5 cm behind the mirror, so the object and the image are further apart.
    • If you chose B: The image is not halfway. It is as far behind the mirror as the object is in front.
    • If you chose C: The image is as far behind the mirror as the object is in front, which is 5 cm, not 10 cm.
  3. A ray of light goes from air into water at a slant. What happens to it?

    Tap your answer.
    1. Yes, that is right. Light is slower in water than in air. A ray that goes into a slower material bends towards the normal.

    2. Not this one. The light does slow down, but a slower speed turns the ray towards the normal, not away from it. Try another.

    3. Not this one. Light is slower in water than in air. It slows down, and that turns the ray towards the normal. Try another.

    4. Not this one. Clear materials still change the speed of light. A ray at a slant bends at the edge. Go to S3.9.2. Try another.

    See the answer

    It bends towards the normal, because the light slows down.

    Light is slower in water than in air. A ray that goes into a slower material bends towards the normal.

    • If you chose B: The light does slow down, but a slower speed turns the ray towards the normal, not away from it.
    • If you chose C: Light is slower in water than in air. It slows down, and that turns the ray towards the normal.
    • If you chose D: Clear materials still change the speed of light. A ray at a slant bends at the edge. Go to S3.9.2.
  4. A ray of light travels along the normal as it goes from air into glass. What happens?

    Tap your answer.
    1. Not this one. It is already on the normal, so there is no angle to bend. The angle of incidence is 0°. Try another.

    2. Not this one. Total internal reflection needs light inside the glass going out, at a large angle. From air into glass, light always goes in. Try another.

    3. Yes, that is right. The angle of incidence is 0°, and sin 0° = 0, so the angle of refraction is also 0°. The ray does not bend, but it slows down in the glass.

    See the answer

    It goes straight on, at a lower speed.

    The angle of incidence is 0°, and sin 0° = 0, so the angle of refraction is also 0°. The ray does not bend, but it slows down in the glass.

    • If you chose A: It is already on the normal, so there is no angle to bend. The angle of incidence is 0°.
    • If you chose B: Total internal reflection needs light inside the glass going out, at a large angle. From air into glass, light always goes in.
  5. Which pair of conditions is needed for total internal reflection?

    Tap your answer.
    1. Not this one. From air into glass, light always crosses. Total internal reflection is for light going from the denser material outwards. Try another.

    2. Not this one. Under the critical angle some light leaves the glass. The angle must be greater than the critical angle. Try another.

    3. Not this one. Glass has a higher index than water, so light going from water into glass bends towards the normal and always crosses. Try another.

    4. Yes, that is right. The light must go from a higher index to a lower index, such as glass to air. The angle of incidence must also be greater than the critical angle.

    See the answer

    Light goes from glass into air, and the angle of incidence is greater than the critical angle.

    The light must go from a higher index to a lower index, such as glass to air. The angle of incidence must also be greater than the critical angle.

    • If you chose A: From air into glass, light always crosses. Total internal reflection is for light going from the denser material outwards.
    • If you chose B: Under the critical angle some light leaves the glass. The angle must be greater than the critical angle.
    • If you chose C: Glass has a higher index than water, so light going from water into glass bends towards the normal and always crosses.
  6. Why does light stay inside a bent glass fibre?

    A glass fibre that runs straight and then bends upwards, shaded with dots and labelled glass fibre. A ray of light enters at the left end and zigzags along the fibre to the top end.glass fibre
    Tap your answer.
    1. Yes, that is right. The ray meets the wall at an angle of incidence greater than the critical angle. So all of it is reflected back inside. It repeats this all along the fibre.

    2. Not this one. Paint would not send the light back. The light is reflected, as in a mirror, by total internal reflection at the glass wall. Try another.

    3. Not this one. Light leaves glass freely at a small angle of incidence. It stays in only when it meets the wall beyond the critical angle. Try another.

    See the answer

    The ray meets the wall beyond the critical angle each time, so it is totally reflected.

    The ray meets the wall at an angle of incidence greater than the critical angle. So all of it is reflected back inside. It repeats this all along the fibre.

    • If you chose B: Paint would not send the light back. The light is reflected, as in a mirror, by total internal reflection at the glass wall.
    • If you chose C: Light leaves glass freely at a small angle of incidence. It stays in only when it meets the wall beyond the critical angle.
  7. A ray goes from air into glass of index 1.5. The angle of incidence is 45°. What is the angle of refraction?

    Tap your answer.
    1. Not this one. You divided the angle by 1.5. The rule uses sines: sin r = sin i ÷ n. Try another.

    2. Yes, that is right. sin r = sin 45° ÷ 1.5 = 0.7071 ÷ 1.5 = 0.4714. The angle whose sine is 0.4714 is 28.1°.

    3. Not this one. You multiplied the angle by 1.5. The ray bends towards the normal, so r must be smaller than 45°, and the rule uses sines. Try another.

    See the answer

    28.1°

    sin r = sin 45° ÷ 1.5 = 0.7071 ÷ 1.5 = 0.4714. The angle whose sine is 0.4714 is 28.1°.

    • If you chose A: You divided the angle by 1.5. The rule uses sines: sin r = sin i ÷ n.
    • If you chose C: You multiplied the angle by 1.5. The ray bends towards the normal, so r must be smaller than 45°, and the rule uses sines.
  8. From an earlier chapter

    A cliff returns the echo of a shout after 2 s. The speed of sound is 340 m/s. How far away is the cliff?

    Tap your answer.
    1. Not this one. That is the whole way there and back. The cliff is half that far away. Go to S4.10.4. Try another.

    2. Not this one. You halved twice. The echo time is the time for the whole way there and back, so halve the distance once. Go to S4.10.4. Try another.

    3. Yes, that is right. The sound goes 340 × 2 = 680 m there and back. The cliff is half of that: 340 m.

    See the answer

    340 m

    The sound goes 340 × 2 = 680 m there and back. The cliff is half of that: 340 m.

    • If you chose A: That is the whole way there and back. The cliff is half that far away. Go to S4.10.4.
    • If you chose B: You halved twice. The echo time is the time for the whole way there and back, so halve the distance once. Go to S4.10.4.
  9. A ray goes from air into glass of index 1.5. The angle of incidence is 50°. What is the angle of refraction, to one decimal place?

    See the answer

    30.7°

    sin r = sin 50° ÷ 1.5 = 0.7660 ÷ 1.5 = 0.5107. The angle whose sine is 0.5107 is 30.7°.

  10. Diamond has a refractive index of 2.42. What is the critical angle for light going from diamond into air, to one decimal place?

    See the answer

    24.4°

    sin c = 1 ÷ n = 1 ÷ 2.42 = 0.4132. The angle whose sine is 0.4132 is 24.4°.

Keep it

Copy this into your exercise book.

Angles are from the normal. Reflection: i = r. Slower material: bends towards the normal. Total internal reflection: denser to less dense, beyond the critical angle, sin c = 1 ÷ n.

Draw: A glass edge with three rays: one bending out, one along the edge, one reflected, and the normal as a dashed line.

Reading with a child? A short page for the adult: what this chapter teaches and three questions to ask.

No internet tomorrow? Save the whole book as one file (951 KB). It opens on any phone.