S4.10.6 Chapter 6

Lenses

Held far from a window, a magnifying glass puts a small, upside down picture of the window on a sheet of paper. Why is the picture upside down?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

By the end you can

  • Draw ray diagrams for a converging lens
  • Explain how lenses correct short sight and long sight

A lens is a clear piece of glass or plastic with curved faces. It bends light by refraction at each face. A converging lens is thicker in the middle and brings parallel rays together. A diverging lens is thinner in the middle and spreads them apart.

The principal focus, F, of a converging lens is the point where rays parallel to the axis meet after the lens. The axis is the line through the middle of the lens at right angles to its faces. The distance from the lens to F is the focal length, f.

A converging lens drawn as an upright shape, labelled lens. Five parallel rays arrive from the left, bend at the lens, and all pass through one point on the axis to the right of the lens, labelled focus. They spread out again beyond it. A dashed line is the axis.lensfocus
Parallel rays meet at the principal focus. A fatter lens bends them more, so its focus is nearer.

A lens works both ways, so it has a focus on each side, at the same distance f. A fatter, more curved lens has a shorter focal length. A real lens bends light at both faces. To keep the picture clear, we draw one bend, at one line through the middle.

To find the image of an object, draw an arrow for the object. Then trace three rays from its tip. These three rules are enough.

Rule one: a ray that travels parallel to the axis bends and goes through the focus on the far side. Rule two: a ray that goes through the centre of the lens carries straight on. Rule three: a ray that passes through the focus on the near side leaves the lens parallel to the axis.

Where the rays meet is the image of the tip. If the rays really cross there, the image is a real image. You can catch it on a screen. It is upside down. The picture of the window is a real image.

A converging lens with an object arrow on the left, labelled object, beyond twice the focal length. A mark F on each side of the lens is the focus, and a mark 2F on each side is twice as far. Three rays from the tip of the object bend at the lens and meet on the right, between F and 2F. A small upside down arrow there is labelled image. The lens is labelled.lensobjectimageFF2F2F
An object beyond 2F gives a real, upside down, smaller image between F and 2F.
A converging lens with an object arrow on the left, labelled object, exactly at 2F. Three rays from the tip bend at the lens and meet at 2F on the right. An upside down arrow of the same size there is labelled image. The marks F and 2F are shown on both sides. The lens is labelled.lensobjectimageFF2F2F
An object at 2F gives a real, upside down image of the same size, also at 2F.
A converging lens with an object arrow on the left, labelled object, between F and 2F. Three rays from the tip bend at the lens and meet far to the right, beyond 2F. A larger upside down arrow there is labelled image. The marks F are shown on both sides. The lens is labelled.lensobjectimageFF
An object between F and 2F gives a real, upside down, larger image beyond 2F.

Move the object closer, to a point inside F. The rays now leave the lens spreading out. They never cross on the far side. Look backwards along the rays, and they seem to come from one point on the object's side.

A converging lens with an object arrow on the left, labelled object, nearer to the lens than F. Three rays from the tip bend at the lens and spread out to the right. Dotted lines go back from the lens to the left and meet behind the object, where a larger upright dashed arrow is labelled image. The marks F are shown on both sides. The lens is labelled.lensobjectimageFF
An object inside F gives an upright, larger image on the same side as the object. This is a magnifying glass.

This image is a virtual image. Light does not really pass through it, so it cannot be caught on a screen. Your eye sees it because the rays seem to come from it. A virtual image from a converging lens is upright and larger. This is how a magnifying glass works.

A table with the columns Object, Image and Size. Row 1: beyond 2F, real, smaller. Row 2: at 2F, real, same. Row 3: 2F to F, real, larger. Row 4: inside F, virtual, larger.ObjectImageSizebeyond 2Frealsmallerat 2Frealsame2F to Freallargerinside Fvirtuallarger
The image from a converging lens. A real image is upside down. A virtual image is upright. An object at F gives no image: the rays leave parallel.

Diagrams give the shape of the answer. A rule gives the numbers. For a thin lens, 1/f = 1/u + 1/v. Here u is the distance from the object to the lens and v is the distance from the lens to the image. All are in the same unit.

This book counts distances to a real image as positive, and a virtual image has a negative v. Other books use other sign rules and write the formula another way. The physics is the same. To find v, rearrange: 1/v = 1/f − 1/u.

The magnification is the height of the image divided by the height of the object. It also equals v ÷ u when you ignore the sign. A magnification of 2 means the image is twice as tall as the object. It has no unit.

Worked example

An object is 4 cm from a converging lens of focal length 3 cm. Find the image distance and the magnification.

  1. For a real image, 1/v = 1/f − 1/u. Here f = 3 cm and u = 4 cm.
  2. 1/v = 1/3 − 1/4 = 4/12 − 3/12 = 1/12.
  3. So v = 12 cm. The image is real and 12 cm from the lens.
  4. The magnification is v ÷ u = 12 ÷ 4 = 3.

Answer: 12 cm and a magnification of 3

A converging lens with an object arrow on the left, labelled object, between F and 2F. Three rays from the tip bend at the lens and meet to the right, beyond 2F. A larger upside down arrow there is labelled image. The marks F are shown on both sides. The lens is labelled.lensobjectimageFF
Any object between F and 2F gives a larger real image, as in the worked example.

Now the diverging lens. It spreads parallel rays so that they seem to come from a focus on the object's side. The three rays bend the other way. A ray parallel to the axis leaves as if from the near focus. A ray through the centre goes straight on. A ray aimed at the focus on the far side leaves parallel to the axis.

A diverging lens drawn as an upright line with arrow heads pointing inwards, labelled lens. An object arrow on the left is labelled object. Three rays from its tip spread out after the lens. Dotted lines go back to the left and meet at the tip of a small upright dashed arrow between the lens and the object, labelled image. The marks F are on both sides.lensobjectimageFF
A diverging lens always gives an upright, smaller, virtual image between the lens and the object.

Now turn to the eye. The cornea and the lens of the eye act together as a converging lens. They make a real, upside down image of what you look at on the retina at the back of the eye. The brain turns the picture the right way up.

A muscle changes the shape of the eye lens. To look at something close, the lens is made fatter, so its focal length is shorter. To look at something far, it is made thinner. This focusing is why a clear eye sees both near and far.

In short sight, the eye bends light too much, or the eyeball is too long. Rays from a far object cross in front of the retina, and the image on the retina is blurred. Near things are clear. A diverging lens in front of the eye spreads the rays a little and moves the image back onto the retina.

A short sighted eye seen from the side, with the retina, labelled retina, at the back and the eye lens, labelled lens, near the front. Three parallel rays arrive from the left, from a far object, labelled far object. They bend at the lens and cross at a point in front of the retina. They then spread out again, so they reach the retina at three different places.lensretinafar object
Short sight without glasses. The rays from a far object meet in front of the retina, so the picture on the retina is blurred.
The same short sighted eye with a diverging lens in front of it, labelled glasses. Three parallel rays from a far object, labelled far object, spread a little at the glasses, bend at the eye lens, labelled lens, and meet exactly at one point on the retina, labelled retina.lensretinaglassesfar object
Short sight corrected with a diverging lens. The rays now meet on the retina.

In long sight, the eye bends light too little, or the eyeball is too short. Rays from a near object would meet behind the retina, so the image on the retina is blurred. Far things are clear. A converging lens in front of the eye helps to bend the rays and moves the image forward onto the retina.

An eye seen from the side, with an object arrow on the left, labelled object. A converging glasses lens stands in front of the eye. The rays from the tip and the foot of the object come together a little at the glasses lens, bend at the eye lens, labelled lens, and meet exactly on the retina, labelled retina. The small upside down image there is labelled image.lensretinaimageobject
Long sight corrected with a converging lens. The image is back on the retina. The object is drawn near, as a book would be.

Opticians give the strength of a lens as its power: P = 1 ÷ f, with f in metres. The unit is the dioptre, D. A converging lens has a positive power and a diverging lens a negative one. A short focal length is a high power.

A short sighted person sees clearly only as far as a distance called the far point. A diverging lens in front of the eye should make a faraway object seem to be at the far point. So its focal length equals the far point distance, with the sign of a diverging lens.

Worked example

A short sighted person sees clearly only up to 0.5 m. What power of lens do they need?

  1. The lens must make faraway things look as if they are 0.5 m away. So it is a diverging lens with focal length 0.5 m.
  2. The size of the power is 1 ÷ f = 1 ÷ 0.5 = 2 D.
  3. A diverging lens has a negative power, so the lens is −2 D.

Answer: The lens is −2 D

Try it

Make a picture with a lens

You need: a lens from an old pair of reading glasses, or a magnifying glass, a sheet of white paper, a ruler, a room with a window or a lamp across the room.

Be safe: Never look at the Sun, and never point a lens at the Sun. A lens focuses sunlight into a hot spot that can burn skin, paper and eyes. Choose a window or a lamp, and keep the Sun out of the view. Do not look into a bright lamp through the lens.

  1. Hold the paper up as a screen, with its back to the window. Hold the lens between the window and the paper.
  2. Move the lens towards and away from the paper until a sharp small picture of the window appears on the paper.
  3. Measure the distance from the lens to the paper. This is about the focal length f, because the window is so far away.
  4. Work out the power: P = 1 ÷ f, with f in metres.

What you will see: The picture on the paper is upside down and smaller than the window. It is a real image. The window is far away, so the image forms very near the focus.

If you cannot try it, this is what happens.
A table with the columns Measure and Value. Row 1: lens to paper, 12 cm. Row 2: focal length f, 0.12 m. Row 3: power 1 ÷ f, 8.3 D.MeasureValuelens to paper12 cmfocal length f0.12 mpower 1 ÷ f8.3 D

A wrong idea many people have

A converging lens always makes an upside down image.

Why it feels right: The first picture we see, a window on a screen, is upside down. Most pictures of lenses show an upside down image.

The test that breaks it: Hold a magnifying glass close to some print. The print looks larger and the right way up. That image is virtual, and the object is inside the focal length.

What is true: A real image from a converging lens is upside down. When the object is inside F, the image is virtual, upright and larger.

A wrong idea many people have

A short sighted person needs a lens that magnifies, so a converging lens.

Why it feels right: We call a magnifying glass a lens that helps us see, and a short sighted person sees things badly.

The test that breaks it: In short sight, the rays from a far object cross in front of the retina. A converging lens would bring them together even sooner, and make it worse.

What is true: Short sight needs a diverging lens, to spread the rays. Long sight needs a converging lens, to bring them together sooner.

A wrong idea many people have

A lens has one focus.

Why it feels right: Pictures of parallel rays arriving from one side show only one point where the rays meet.

The test that breaks it: Turn the lens round and send the rays from the other side. They meet at a point the same distance from the lens on the other side.

What is true: A lens has a focus on each side, at the same distance f. Rule three uses the focus on the object's side.

Key words

principal focus
the point where rays that arrive parallel to the axis meet after a converging lens.
focal length
the distance from the lens to its principal focus. Its symbol is f.
real image
an image where rays really cross. It can be caught on a screen, and it is upside down.
virtual image
an image where the rays only seem to cross. It cannot be caught on a screen.
magnification
the height of the image divided by the height of the object.
short sight
a fault in which far things are blurred. A diverging lens corrects it.
power
the strength of a lens, P = 1 ÷ f with f in metres.
dioptre
the unit of the power of a lens, written D.

Back to your guess

The answer is A: Rays from the top of the window cross after the lens and reach the bottom of the picture.

Rays from the top of the window go through the lens, bend, and cross. After crossing they are below the axis, so they land at the bottom of the picture. Rays from the bottom land at the top. So the picture is upside down.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. A ray travels parallel to the axis towards a converging lens. Where does it go after the lens?

    Tap your answer.
    1. Not this one. Only a ray through the centre of the lens goes straight on. A ray that is off the centre is bent towards the focus. Try another.

    2. Not this one. A ray leaves a lens parallel to the axis only if it passed through the near focus. A ray that arrives parallel is bent. Try another.

    3. Not this one. The bend carries the ray across the axis, to the focus on the far side of the lens. Try another.

    4. Yes, that is right. Rule one: a ray that arrives parallel to the axis goes through the focus on the far side of a converging lens.

    See the answer

    Through the focus on the far side

    Rule one: a ray that arrives parallel to the axis goes through the focus on the far side of a converging lens.

    • If you chose A: Only a ray through the centre of the lens goes straight on. A ray that is off the centre is bent towards the focus.
    • If you chose B: A ray leaves a lens parallel to the axis only if it passed through the near focus. A ray that arrives parallel is bent.
    • If you chose C: The bend carries the ray across the axis, to the focus on the far side of the lens.
  2. The picture shows an object beyond 2F from a converging lens. What kind of image does the lens make?

    A converging lens with an object arrow on the left, labelled object, beyond twice the focal length. The marks F on both sides are the focus, and the marks 2F on both sides are twice as far. Three rays from the tip of the object are drawn as far as the lens only. The lens is labelled.lensobjectFF2F2F
    Tap your answer.
    1. Not this one. That is for an object inside F. Here the object is beyond 2F, and the rays do cross on the far side. Try another.

    2. Yes, that is right. An object beyond 2F gives a real image between F and 2F on the other side. It is upside down and smaller than the object.

    3. Not this one. A real image from a converging lens is always upside down. This one is smaller, because the object is beyond 2F. Try another.

    4. Not this one. A virtual image from a converging lens is upright. This object is beyond 2F, so the image is real. Try another.

    See the answer

    Real, upside down and smaller

    An object beyond 2F gives a real image between F and 2F on the other side. It is upside down and smaller than the object.

    • If you chose A: That is for an object inside F. Here the object is beyond 2F, and the rays do cross on the far side.
    • If you chose C: A real image from a converging lens is always upside down. This one is smaller, because the object is beyond 2F.
    • If you chose D: A virtual image from a converging lens is upright. This object is beyond 2F, so the image is real.
  3. An object is 20 cm from a converging lens of focal length 15 cm. How far from the lens is the image?

    Tap your answer.
    1. Not this one. You added 15 and 20. The rule works with reciprocals: 1/v = 1/f − 1/u. Try another.

    2. Not this one. You added the reciprocals. The rule has a minus: 1/v = 1/f − 1/u. Try another.

    3. Yes, that is right. 1/v = 1/15 − 1/20 = 4/60 − 3/60 = 1/60. So v = 60 cm.

    See the answer

    60 cm

    1/v = 1/15 − 1/20 = 4/60 − 3/60 = 1/60. So v = 60 cm.

    • If you chose A: You added 15 and 20. The rule works with reciprocals: 1/v = 1/f − 1/u.
    • If you chose B: You added the reciprocals. The rule has a minus: 1/v = 1/f − 1/u.
  4. An object is 3 cm from a converging lens of focal length 5 cm. Which describes the image?

    Tap your answer.
    1. Yes, that is right. The object is nearer than F. The rays spread out after the lens, and look as if they come from a larger, upright, virtual image. This is how a magnifying glass works.

    2. Not this one. The object is inside F, so the rays leave the lens spreading out and they do not cross on the far side. Try another.

    3. Not this one. A small real image needs the object beyond 2F. This object is inside F. Try another.

    4. Not this one. No image forms only when the object is exactly at F. Inside F there is a virtual image. Try another.

    See the answer

    Virtual, upright and larger

    The object is nearer than F. The rays spread out after the lens, and look as if they come from a larger, upright, virtual image. This is how a magnifying glass works.

    • If you chose B: The object is inside F, so the rays leave the lens spreading out and they do not cross on the far side.
    • If you chose C: A small real image needs the object beyond 2F. This object is inside F.
    • If you chose D: No image forms only when the object is exactly at F. Inside F there is a virtual image.
  5. Which lens corrects short sight?

    Tap your answer.
    1. Not this one. In short sight the rays already meet too soon. A converging lens would make them meet even sooner. Try another.

    2. Yes, that is right. In short sight, rays from a far object meet in front of the retina. A diverging lens spreads them, so that they meet on the retina.

    3. Not this one. Flat glass does not bend rays that arrive straight on. The eye needs rays that are spread a little. Try another.

    See the answer

    A diverging lens

    In short sight, rays from a far object meet in front of the retina. A diverging lens spreads them, so that they meet on the retina.

    • If you chose A: In short sight the rays already meet too soon. A converging lens would make them meet even sooner.
    • If you chose C: Flat glass does not bend rays that arrive straight on. The eye needs rays that are spread a little.
  6. A long sighted person cannot see near things clearly. What goes wrong in the eye?

    Tap your answer.
    1. Not this one. That is what happens in short sight. In long sight the eye bends the rays too little. Try another.

    2. Not this one. The picture is blurred, not too small. The rays do not meet on the retina. Try another.

    3. Yes, that is right. The eye bends light too little, or the eyeball is too short. So the rays from a near object would meet behind the retina. A converging lens in glasses helps.

    See the answer

    The rays from a near object would meet behind the retina.

    The eye bends light too little, or the eyeball is too short. So the rays from a near object would meet behind the retina. A converging lens in glasses helps.

    • If you chose A: That is what happens in short sight. In long sight the eye bends the rays too little.
    • If you chose B: The picture is blurred, not too small. The rays do not meet on the retina.
  7. A lens has a focal length of 25 cm. What is its power?

    Tap your answer.
    1. Not this one. That is the focal length in cm, not the power. The power is 1 divided by the focal length in metres. Try another.

    2. Not this one. 0.25 is the focal length in metres. The power is 1 divided by it. Try another.

    3. Not this one. You worked out 1 ÷ 25, with f in cm. Change f to metres first: 25 cm is 0.25 m. Try another.

    4. Yes, that is right. First change to metres: 25 cm = 0.25 m. Then P = 1 ÷ f = 1 ÷ 0.25 = 4 D.

    See the answer

    4 D

    First change to metres: 25 cm = 0.25 m. Then P = 1 ÷ f = 1 ÷ 0.25 = 4 D.

    • If you chose A: That is the focal length in cm, not the power. The power is 1 divided by the focal length in metres.
    • If you chose B: 0.25 is the focal length in metres. The power is 1 divided by it.
    • If you chose C: You worked out 1 ÷ 25, with f in cm. Change f to metres first: 25 cm is 0.25 m.
  8. From an earlier chapter

    A dense crystal has a refractive index of 2.0. What is the critical angle for light going from it into air?

    Tap your answer.
    1. Yes, that is right. sin c = 1 ÷ n = 1 ÷ 2.0 = 0.5. The angle whose sine is 0.5 is 30°.

    2. Not this one. That is 90° − 30°. The critical angle is the angle whose sine is 1 ÷ n, which is 0.5. Go to S4.10.5. Try another.

    3. Not this one. That is the angle whose tangent is 0.5. The rule uses the sine: sin c = 1 ÷ n. Go to S4.10.5. Try another.

    See the answer

    30°

    sin c = 1 ÷ n = 1 ÷ 2.0 = 0.5. The angle whose sine is 0.5 is 30°.

    • If you chose B: That is 90° − 30°. The critical angle is the angle whose sine is 1 ÷ n, which is 0.5. Go to S4.10.5.
    • If you chose C: That is the angle whose tangent is 0.5. The rule uses the sine: sin c = 1 ÷ n. Go to S4.10.5.
  9. An object is 20 cm from a converging lens of focal length 12 cm. How far from the lens is the image?

    See the answer

    30 cm

    1/v = 1/12 − 1/20 = 5/60 − 3/60 = 2/60 = 1/30. So v = 30 cm.

  10. A lens has a focal length of 40 cm. What is its power in dioptres?

    See the answer

    2.5 D

    Change to metres: 40 cm = 0.4 m. Then P = 1 ÷ f = 1 ÷ 0.4 = 2.5 D.

Keep it

Copy this into your exercise book.

Three rays: parallel through the far focus, through the centre straight, through the near focus out parallel. 1/f = 1/u + 1/v. Short sight: diverging. Long sight: converging. P = 1 ÷ f.

Draw: A converging lens with its axis and F marks, an object arrow, and the three rays meeting at an upside down image.

Reading with a child? A short page for the adult: what this chapter teaches and three questions to ask.

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