M4.8.3 Chapter 3
Inequalities
The answer to 3x − 4 < 11 is not one number. How do I show every answer?
Your guess
Pick one before you read on. It is fine to be wrong.
By the end you can
- Solve 3x − 4 < 11 and show it on a number line
- Solve an inequality where you must flip the sign
- List the whole numbers that fit −2 < x ≤ 3
A bridge sign says: loads must be less than 5 tonnes. A load of 4 tonnes is allowed. So is 3, and so is 0.5. Many numbers fit. We write the rule as x < 5.
The sign < means "is less than". The sign > means "is more than". The sign ≤ means "is less than or equal to". The sign ≥ means "is more than or equal to". A statement with one of these signs is an inequality.
Draw it first
Show x < 5 on a number line
1 Draw a number line. Put an open circle at 5. It is open because 5 is not allowed: x is less than 5, not equal to 5.
2 Draw a thick bar from the circle towards the smaller numbers. The arrow says it goes on for ever.
3 Dots on the whole numbers 4, 3, 2, 1, 0 and −1 show a few of the numbers that fit. The arrow shows there are more.
An open circle means the end number is not included. It goes with < and >. A filled circle means the end number is included. It goes with ≤ and ≥.
Now solve 3x − 4 < 11. Treat it like an equation and do the same to both sides. Adding 4 to both sides gives 3x < 15. A balance shows this. Say a bag weighs 4 kg. Then 3 bags weigh 12 kg, and the other pan holds 15 kg. The 15 kg side is heavier, so the beam tilts.
Worked example
Solve 3x − 4 < 11 and show it on a number line.
- Add 4 to both sides. The sign stays the same: 3x < 15.
- Divide both sides by 3. The sign stays the same: x < 5.
- Test it. When x = 4, 3x − 4 = 8, which is less than 11. When x = 6, 3x − 4 = 14, which is not.
- On the number line put an open circle at 5 with a bar going left.
Answer: x < 5
Now a trap. On a number line the bigger number is always further right. 2 is left of 5, so 2 < 5. Multiply both numbers by −1 and look again.
Multiplying by −1 swaps left and right. So multiplying or dividing both sides by a negative number must flip the sign: < becomes > and > becomes <. Adding or taking away never flips it. Neither does multiplying or dividing by a positive number.
Worked example
Solve 7 − 2x > 1.
- Take 7 from both sides. The sign stays the same: −2x > −6.
- Divide both sides by −2. The number is negative, so the sign flips: x < 3.
- Test it. When x = 0, 7 − 2x = 7, which is more than 1. When x = 4, 7 − 2x = −1, which is not.
Answer: x < 3
Sometimes x is boxed in on both sides. The inequality −2 < x ≤ 3 means x is more than −2 and also at most 3. The circle at −2 is open, and the circle at 3 is filled.
Worked example
List the whole numbers that fit −2 < x ≤ 3.
- Read it as two rules. x is more than −2, and x is at most 3.
- The circle at −2 is open, so −2 does not fit. The first whole number is −1.
- The circle at 3 is filled, so 3 does fit. The last whole number is 3.
- The whole numbers are −1, 0, 1, 2, 3.
- Count them. There are 5 whole numbers.
Answer: −1, 0, 1, 2, 3
See it three ways
With things
A shelf holds fewer than 5 books. It might hold none. How many books could be on it?
As a picture
In words
The shelf holds 0, 1, 2, 3 or 4 books. It cannot hold 5, because 5 is not fewer than 5.
In symbols
x is a whole number with 0 ≤ x < 5.
Try it
Mark a rule with stones
You need: paper and a pencil, a few small stones or coins.
- Draw a number line from 0 to 8 and write the numbers under it.
- The rule is x ≥ 3. Put a stone on every whole number that fits.
- Mark 3 with a filled circle and draw a bar with an arrow to the right.
What you will see: The stones sit on 3, 4, 5, 6, 7 and 8. The number 3 has a stone because ≥ includes it, so the circle is filled. The arrow shows that 9, 10 and every bigger number fit too.
A wrong idea many people have
You flip the sign whenever you divide.
Why it feels right: Flipping is the new rule, so it feels as if it applies to every division.
The test that breaks it: Solve 3x < 15. Dividing by 3 gives x < 5. Put x = 4: 3 × 4 = 12, which is less than 15. A flipped sign, x > 5, would say 4 is not allowed.
What is true: The sign flips only when you multiply or divide both sides by a negative number. Dividing by 3 is dividing by a positive number.
A wrong idea many people have
x > 3 and x ≥ 3 mean the same.
Why it feels right: The two signs look almost the same, and both point to the bigger numbers.
The test that breaks it: Put x = 3. Then 3 ≥ 3 is true, because 3 equals 3. But 3 > 3 is false.
What is true: x > 3 leaves 3 out, with an open circle. x ≥ 3 keeps 3, with a filled circle.
Key words
- inequality
- a statement that one thing is less than, more than, at most or at least another. Two examples are x < 5 and x ≥ 3.
- open circle
- a ring on a number line. It shows the end number is not included.
- filled circle
- a solid dot on a number line. It shows the end number is included.
Back to your guess
The answer is C: x < 5, and every number below 5 fits.
An inequality has many answers. 3x − 4 < 11 gives 3x < 15, so x < 5. Every number below 5 fits. The sign flips only when you multiply or divide both sides by a negative number.
Check yourself
Try each one before you look. A wrong answer tells you where to go next.
Which inequality does the number line show?
See the answer
x > 4
The bar goes right, so x is more than 4. The circle is open, so 4 itself is not included.
Solve 2x + 3 < 11.
See the answer
x < 4
Take 3 from both sides: 2x < 8. Divide both sides by 2: x < 4. The sign stays because 2 is positive.
- If you chose A: You added 3 to the 11. The 3 is added on the left, so take it from both sides instead. Go to M4.8.3.
- If you chose B: Taking 3 from 11 gives 2x < 8, which is right. But 2x < 8 still needs dividing by 2. Go to M4.8.3.
- If you chose C: The sign flips only when you multiply or divide by a negative number. Dividing by 2 keeps the sign. Go to M4.8.3.
Solve 9 − 2x < 3.
See the answer
x > 3
Take 9 from both sides: −2x < −6. Divide both sides by −2 and flip the sign: x > 3. Test x = 4: 9 − 8 = 1, which is less than 3.
Which list holds all the whole numbers that fit −3 < x ≤ 2?
See the answer
−2, −1, 0, 1, 2
x is more than −3, so −3 is out and −2 is the first. Also x is at most 2, so 2 is in. That gives five whole numbers.
- If you chose A: The circle at −3 is open, so −3 is not included. The list must start at −2. Go to M4.8.3.
- If you chose B: The circle at 2 is filled, so 2 is included. The list must end at 2. Go to M4.8.3.
- If you chose D: This includes −3, which has an open circle, and leaves out 2, which has a filled circle. The ends are the wrong way round. Go to M4.8.3.
A number line has a filled circle at 2 and a bar going left. What does it show?
See the answer
x ≤ 2, and the end point is included.
The bar goes left, so x is at most 2. The circle is filled, so 2 itself is included.
Which step needs the sign of the inequality to be flipped?
See the answer
−4x < 20, divided by −4 on both sides
Only this step divides by a negative number. Dividing both sides of −4x < 20 by −4 gives x > −5, and the sign flips.
- If you chose A: The number 4 is positive. Dividing by a positive number keeps the sign the same. Go to M4.8.3.
- If you chose C: Adding or taking away never flips the sign. Only multiplying or dividing by a negative number does. Go to M4.8.3.
- If you chose D: The number 2 is positive. Multiplying by a positive number keeps the sign the same. Go to M4.8.3.
Solve 5x + 2 < 17.
See the answer
x < 3
Take 2 from both sides: 5x < 15. Divide both sides by 5. The sign stays, because 5 is positive: x < 3.
- If you chose B: The sign flips only when you multiply or divide both sides by a negative number. Here you divide by 5, which is positive, so the sign stays. Go to M4.8.3.
- If you chose C: Taking 2 from both sides gives 5x < 15, which is right. But 5 still multiplies x, so divide both sides by 5 as well. Go to M4.8.3.
- If you chose D: You added 2 to the 17. The 2 is added to 5x, so take it from both sides: 5x < 15. Go to M4.8.3.
Solve 14 − 2x < 6.
See the answer
x > 4
Take 14 from both sides: −2x < −8. Divide both sides by −2 and flip the sign: x > 4. Test x = 5: 14 − 10 = 4, which is less than 6.
- If you chose A: You divided both sides by −2 but kept the sign. Dividing by a negative number turns < into >. Go to M4.8.3.
- If you chose B: You flipped the sign, which is right. But −8 ÷ −2 is +4, because a negative divided by a negative is positive. Go to M4.8.3.
- If you chose C: Taking 14 from both sides gives −2x < −8, which is right. But −2 still multiplies x, so divide both sides by −2 as well. Go to M4.8.3.
Solve 4x + 5 < 29. What number must x be less than?
See the answer
6
Take 5 from both sides: 4x < 24. Divide both sides by 4. The sign stays, so x < 6.
Solve 19 − 3x < 4. What number must x be more than?
See the answer
5
Take 19 from both sides: −3x < −15. Divide both sides by −3 and flip the sign, so x > 5.
From an earlier chapter
Use t = (v − u)/a with v = 41, u = 5 and a = 9. What is t?
See the answer
t = 4
Put the numbers in: t = (41 − 5)/9 = 36/9 = 4.
Keep it
Copy this into your exercise book.
Open circle: not included. Filled circle: included. Solve like an equation. Flip the sign only when you multiply or divide by a negative number.
Draw: A number line with an open circle at 5 and a bar going left, and the words x < 5.