M4.8.5 Chapter 5

Two equations: adding or taking away

I know x + y = 10 and x − y = 2. How do I find both numbers?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

By the end you can

  • Solve two equations by getting rid of one letter
  • Multiply an equation first so the numbers match

Amina thinks of two numbers, x and y. She says: "Their sum is 10." That alone has many answers. 4 and 6 work, and so do 5 and 5. One clue is not enough for two unknown numbers.

A table with the head x, y, x + y, x − y. Rows: 4, 6, 10, −2; 5, 5, 10, 0; 6, 4, 10, 2; 7, 3, 10, 4.xyx + yx − y4610−2551006410273104
Every pair adds to 10. Only x = 6 and y = 4 also gives x − y = 2.

Amina adds a second clue: "Their difference is 2", so x − y = 2. Now both equations must be true at the same time. Two equations like this are called simultaneous equations.

Look at the y terms. One equation has +y and the other has −y. If you add the two equations, the y terms cancel. This is elimination: you remove one letter.

Why may you add two equations? x + y and 10 are the same amount, and so are x − y and 2. Add equal amounts to equal amounts and the totals are equal too. It is like putting the same weight on both pans of a level balance. Taking equal amounts from equal amounts works the same way.

Draw it first

Add the equations

  1. Two equations written one under the other, labelled (1) and (2): x + y = 10 and x − y = 2. Step 2 hatches the sign and y columns, which cancel. Step 3 adds a result row under a line, labelled (1) + (2): 2x = 12.x+y=10(1)x−y=2(2)

    1 Write the two equations one under the other, with the same letters in the same columns.

  2. Two equations written one under the other, labelled (1) and (2): x + y = 10 and x − y = 2. Step 2 hatches the sign and y columns, which cancel. Step 3 adds a result row under a line, labelled (1) + (2): 2x = 12.x+y=10(1)x−y=2(2)x+y=10(1)x−y=2(2)

    2 The y terms are +y and −y. They cancel when you add, so mark them.

  3. Two equations written one under the other, labelled (1) and (2): x + y = 10 and x − y = 2. Step 2 hatches the sign and y columns, which cancel. Step 3 adds a result row under a line, labelled (1) + (2): 2x = 12.x+y=10(1)x−y=2(2)x+y=10(1)x−y=2(2)x+y=10(1)x−y=2(2)2x=12(1) + (2)

    3 Add the left sides and add the right sides. x + x = 2x, and 10 + 2 = 12. So 2x = 12.

Worked example

Solve x + y = 10 and x − y = 2.

  1. Add the equations. The y terms cancel: 2x = 12.
  2. Divide both sides by 2: x = 6.
  3. Put x = 6 in x + y = 10. Then 6 + y = 10, so y = 4.
  4. Check in the other equation, x − y = 2: 6 − 4 = 2.

Answer: x = 6, y = 4

Sometimes both equations have the same term. Then the sign of the terms is the same, so you subtract. Take 3x + 2y = 19 and x + 2y = 9. Both have +2y.

Two equations labelled (1) and (2): 3x + 2y = 19 and x + 2y = 9. The sign and 2y columns are hatched. Under a line, labelled (1) − (2): 2x = 10.3x+2y=19(1)x+2y=9(2)2x=10(1) − (2)
The 2y terms match and have the same sign, so subtract: 3x − x = 2x and 19 − 9 = 10.

Worked example

Solve 3x + 2y = 19 and x + 2y = 9.

  1. The y terms are both +2y, so subtract equation (2) from equation (1). Then 2x = 10.
  2. Divide both sides by 2: x = 5.
  3. Put x = 5 in equation (2): 5 + 2y = 9, so 2y = 4 and y = 2.
  4. Check in equation (1): 3 × 5 + 2 × 2 = 19.

Answer: x = 5, y = 2

The rule is: if the signs of the matching terms are different, add. If they are the same, subtract. Always do the same to every term, on both sides of the equals sign.

What if no letter matches? Multiply an equation first. Multiplying every term of an equation by the same number keeps it true. Use it to make one letter match.

Two equations labelled (1) and (2): 2x + 3y = 12 and 3x + 2y = 13. Beside them are the notes × 3 and × 2, the numbers to multiply each equation by.2x+3y=12(1)× 33x+2y=13(2)× 2
Multiply (1) by 3 and (2) by 2. Then both have 6x.
Two equations labelled (3) and (4): 6x + 9y = 36 and 6x + 4y = 26. The 6x column is hatched. Under a line, labelled (3) − (4): 5y = 10.6x+9y=36(3)6x+4y=26(4)5y=10(3) − (4)
Call the new equations (3) and (4). The 6x terms match and have the same sign. Subtract: 9y − 4y = 5y and 36 − 26 = 10.

Worked example

Solve 2x + 3y = 12 and 3x + 2y = 13.

  1. Make the x terms match. Multiply (1) by 3 and (2) by 2. Call the new equations (3) and (4): 6x + 9y = 36 and 6x + 4y = 26.
  2. The x terms have the same sign, so subtract (4) from (3): 5y = 10.
  3. Divide both sides by 5: y = 2.
  4. Put y = 2 in equation (1): 2x + 6 = 12, so 2x = 6 and x = 3.
  5. Check in equation (2): 3 × 3 + 2 × 2 = 13.

Answer: x = 3, y = 2

See it three ways

With things

Two bags of rice and one bag of beans weigh 7 kg. One bag of rice and one bag of beans weigh 4 kg. How heavy is a bag of rice?

As a picture

Two bars. The first has two parts marked r and one part marked b, with a bracket labelled 7 kg. The second has one part marked r and one part marked b, with a bracket labelled 4 kg. Each r is 3 long and b is 1 long.rrb7 kgrb4 kg

In words

The first weighing has one more bag of rice. The extra 7 − 4 = 3 kg is one bag of rice. The beans are 4 − 3 = 1 kg.

In symbols

2r + b = 7 and r + b = 4. Subtract: r = 3. Put it back: 3 + b = 4, so b = 1.

Try it

The sum and the difference

You need: paper and a pencil, a friend.

  1. Think of two whole numbers. Say them to yourself and keep them secret.
  2. Tell your friend their sum and their difference, the bigger minus the smaller.
  3. Your friend adds the sum and the difference, then halves the answer. That is your bigger number.

What you will see: The sum plus the difference is twice the bigger number, because the smaller number cancels. Take the bigger number from the sum to find the smaller.

If you cannot try it, this is what happens.
Two equations labelled (1) and (2): x + y = 9 and x − y = 3. The sign and y columns are hatched. Under a line, labelled (1) + (2): 2x = 12.x+y=9(1)x−y=3(2)2x=12(1) + (2)

A wrong idea many people have

To eliminate a letter you always add the equations.

Why it feels right: The first example was solved by adding, so adding feels like the method.

The test that breaks it: Take x + y = 10 and x + 3y = 14. Adding gives 2x + 4y = 24, which still has both letters. Subtracting gives −2y = −4, so y = 2, which has one letter.

What is true: Add when the matching terms have different signs. Subtract when they have the same sign.

A wrong idea many people have

When you multiply an equation, you multiply only the term you want to match.

Why it feels right: You are only trying to change one number, so changing one number feels enough.

The test that breaks it: Multiply x + y = 4 by 3 on the x only: 3x + y = 4. Now x = 1, y = 3 does not fit it: 3 + 3 = 6, not 4. But 1 + 3 = 4 fitted the original.

What is true: Multiply every term on both sides by the same number. Then the new equation says the same thing as the old one.

Key words

simultaneous equations
two or more equations that must be true at the same time.
elimination
removing one letter by adding or subtracting the equations.

Back to your guess

The answer is B: x = 6 and y = 4, because 6 + 4 = 10 and 6 − 4 = 2.

Both equations must be true at once. x = 6 and y = 4 fit both: 6 + 4 = 10 and 6 − 4 = 2. The other pairs fit only the first equation.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. You add x + y = 12 and x − y = 4. What do you get?

    Tap your answer.
    1. Not this one. That is what you get by subtracting the second equation from the first. Here you add, and the y terms cancel. Go to M4.8.5. Try another.

    2. Not this one. x + x is 2x, not x. Adding the left sides gives 2x. Go to M4.8.5. Try another.

    3. Yes, that is right. Add the left sides: x + y + x − y = 2x. Add the right sides: 12 + 4 = 16. So 2x = 16.

    4. Not this one. The right sides are added too: 12 + 4 = 16, not 12 − 4. Go to M4.8.5. Try another.

    See the answer

    2x = 16

    Add the left sides: x + y + x − y = 2x. Add the right sides: 12 + 4 = 16. So 2x = 16.

    • If you chose A: That is what you get by subtracting the second equation from the first. Here you add, and the y terms cancel. Go to M4.8.5.
    • If you chose B: x + x is 2x, not x. Adding the left sides gives 2x. Go to M4.8.5.
    • If you chose D: The right sides are added too: 12 + 4 = 16, not 12 − 4. Go to M4.8.5.
  2. Look at 3x + 2y = 16 and x + 2y = 8. What is the quickest way to eliminate y?

    Tap your answer.
    1. Yes, that is right. Both equations have +2y. Matching terms with the same sign are removed by subtracting: 3x − x = 2x, and 16 − 8 = 8.

    2. Not this one. Adding gives 4x + 4y = 24, which still has y. The 2y terms have the same sign, so subtract. Go to M4.8.5. Try another.

    3. Not this one. This does not make the y terms match. It gives 1.5x + y = 8, and the other equation still has 2y. Go to M4.8.5. Try another.

    See the answer

    Subtract the second equation from the first.

    Both equations have +2y. Matching terms with the same sign are removed by subtracting: 3x − x = 2x, and 16 − 8 = 8.

    • If you chose B: Adding gives 4x + 4y = 24, which still has y. The 2y terms have the same sign, so subtract. Go to M4.8.5.
    • If you chose C: This does not make the y terms match. It gives 1.5x + y = 8, and the other equation still has 2y. Go to M4.8.5.
  3. Solve 2x + y = 13 and x + y = 8. What are x and y?

    Tap your answer.
    1. Not this one. You swapped the two answers. Check in 2x + y = 13: 2 × 3 + 5 = 11, not 13. Go to M4.8.5. Try another.

    2. Not this one. Subtracting gives x = 5. Then y is not 8: put x = 5 in x + y = 8 to find y. Go to M4.8.5. Try another.

    3. Not this one. Check in 2x + y = 13: 2 × 4 + 4 = 12, not 13. The pair must fit both equations. Go to M4.8.5. Try another.

    4. Yes, that is right. Subtract the second equation from the first: x = 13 − 8 = 5. Put x = 5 in x + y = 8: y = 3. Check: 2 × 5 + 3 = 13.

    See the answer

    x = 5, y = 3

    Subtract the second equation from the first: x = 13 − 8 = 5. Put x = 5 in x + y = 8: y = 3. Check: 2 × 5 + 3 = 13.

    • If you chose A: You swapped the two answers. Check in 2x + y = 13: 2 × 3 + 5 = 11, not 13. Go to M4.8.5.
    • If you chose B: Subtracting gives x = 5. Then y is not 8: put x = 5 in x + y = 8 to find y. Go to M4.8.5.
    • If you chose C: Check in 2x + y = 13: 2 × 4 + 4 = 12, not 13. The pair must fit both equations. Go to M4.8.5.
  4. Look at x + 2y = 7 and 3x − y = 7. What should you do first to eliminate y?

    Tap your answer.
    1. Not this one. Adding gives 4x + y = 14, which still has y. The y terms are 2y and −y, which do not match. Go to M4.8.5. Try another.

    2. Yes, that is right. Multiplying the second equation by 2 gives 6x − 2y = 14. Now the y terms are +2y and −2y, so adding removes them: 7x = 21.

    3. Not this one. The y terms would be 2y and −2y, which have different signs. Different signs are added, not subtracted. Go to M4.8.5. Try another.

    4. Not this one. That makes the x terms 3x and 3x, with the same sign, so adding gives 6x, not 0. It is the y terms you want to cancel. Go to M4.8.5. Try another.

    See the answer

    Multiply the second equation by 2, then add.

    Multiplying the second equation by 2 gives 6x − 2y = 14. Now the y terms are +2y and −2y, so adding removes them: 7x = 21.

    • If you chose A: Adding gives 4x + y = 14, which still has y. The y terms are 2y and −y, which do not match. Go to M4.8.5.
    • If you chose C: The y terms would be 2y and −2y, which have different signs. Different signs are added, not subtracted. Go to M4.8.5.
    • If you chose D: That makes the x terms 3x and 3x, with the same sign, so adding gives 6x, not 0. It is the y terms you want to cancel. Go to M4.8.5.
  5. The bars show two weighings of bags a and b. How heavy is one bag a?

    Two bars. The first has two parts marked a and one part marked b, with a bracket labelled 11 kg. The second has one part marked a and one part marked b, with a bracket labelled 7 kg.aab11 kgab7 kg
    Tap your answer.
    1. Not this one. That is the weight of b. Take the second weighing from the first to find a, then find b. Go to M4.8.5. Try another.

    2. Not this one. That is the total of one a and one b, not a alone. Go to M4.8.5. Try another.

    3. Not this one. You added the two weighings. To remove b, take one weighing away from the other. Go to M4.8.5. Try another.

    4. Yes, that is right. The first weighing has one more a. The difference 11 − 7 = 4 kg is one bag a.

    See the answer

    4 kg

    The first weighing has one more a. The difference 11 − 7 = 4 kg is one bag a.

    • If you chose A: That is the weight of b. Take the second weighing from the first to find a, then find b. Go to M4.8.5.
    • If you chose B: That is the total of one a and one b, not a alone. Go to M4.8.5.
    • If you chose C: You added the two weighings. To remove b, take one weighing away from the other. Go to M4.8.5.
  6. The y terms are +4y in one equation and −4y in the other. What do you do to eliminate y?

    Tap your answer.
    1. Not this one. Taking −4y away from +4y gives 8y, not 0. Terms with different signs are added. Go to M4.8.5. Try another.

    2. Not this one. The numbers already match. Multiplying would change them and they would no longer cancel. Go to M4.8.5. Try another.

    3. Yes, that is right. +4y and −4y add to 0. Add the left sides and add the right sides, and the y terms cancel.

    4. Not this one. You cannot divide by a letter that may be 0, and it does not remove the y terms anyway. Go to M4.8.5. Try another.

    See the answer

    Add the equations.

    +4y and −4y add to 0. Add the left sides and add the right sides, and the y terms cancel.

    • If you chose A: Taking −4y away from +4y gives 8y, not 0. Terms with different signs are added. Go to M4.8.5.
    • If you chose B: The numbers already match. Multiplying would change them and they would no longer cancel. Go to M4.8.5.
    • If you chose D: You cannot divide by a letter that may be 0, and it does not remove the y terms anyway. Go to M4.8.5.
  7. Solve x + y = 13 and x − y = 5. Give x first, then y.

    See the answer

    x = 9, y = 4

    Add the equations: 2x = 18, so x = 9. Then 9 + y = 13, so y = 4.

  8. Solve 3x + y = 14 and 2x + 3y = 14. Give x first, then y.

    See the answer

    x = 4, y = 2

    Multiply the first equation by 3: 9x + 3y = 42. Subtract the second: 7x = 28, so x = 4. Then 12 + y = 14, so y = 2.

  9. From an earlier chapter

    Find the gradient of the line through (1, 2) and (4, 11).

    See the answer

    3

    The rise is 11 − 2 = 9 and the run is 4 − 1 = 3. The gradient is 9 ÷ 3 = 3.

Keep it

Copy this into your exercise book.

Match one letter, multiplying an equation if you must. Different signs: add. Same signs: subtract. Find the other letter, then check in both equations.

Draw: Two equations under each other with the matching column hatched, a line, and the result row under it.

Reading with a child? A short page for the adult: what this chapter teaches and three questions to ask.

No internet tomorrow? Save the whole book as one file (989 KB). It opens on any phone.