M4.9.1 Chapter 1
Expanding two brackets
I know 3(x + 4) = 3x + 12. What do I do when both parts are brackets, like (x + 3)(x + 2)?
Your guess
Pick one before you read on. It is fine to be wrong.
By the end you can
- Expand (x + 3)(x − 5)
- Expand (2x + 1)² without losing the middle term
Amina knows that 3(x + 4) means 3 × x and 3 × 4. The 3 multiplies each part of the bracket. This is called expanding the bracket.
Now take (x + 3)(x + 2). Picture a rectangle that is x + 3 long and x + 2 wide. Its area is the two brackets multiplied together.
The four parts are the four products. x times x is x². x times 2 is 2x. 3 times x is 3x. 3 times 2 is 6. The parts 3x and 2x are alike, so they join: 5x.
Draw it first
Multiply every pair of terms
1 Start with the two brackets, (x + 3)(x + 2).
2 Multiply every term in the first bracket by every term in the second. There are 2 × 2 = 4 products.
3 Join the like terms. 2x + 3x = 5x, so the answer is x² + 5x + 6.
A term with a minus sign needs care. A positive number times a negative number is negative. A negative times a negative is positive. Here is a pattern that shows why.
A grid keeps the four products in order. Write one bracket across the top and the other down the side. Each cell holds the product of the terms at the ends of its row and column.
Worked example
Expand (x + 3)(x − 5).
- Write the four products: x × x = x², x × (−5) = −5x, 3 × x = 3x and 3 × (−5) = −15.
- Add them up: x² − 5x + 3x − 15.
- Join the x terms. The numbers in front are −5 and 3, and −5 + 3 = −2.
- So the x terms make −2x, and (x + 3)(x − 5) = x² − 2x − 15.
Answer: x² − 2x − 15
You can test an expansion with a number. Put the same value of x into the brackets and into your answer. A right expansion gives the same number both ways.
A bracket squared is the bracket times itself. (2x + 1)² means (2x + 1)(2x + 1). It has four products, not two. The two middle products are equal, and together they make the middle term.
Worked example
Expand (2x + 1)².
- Write the square as two brackets: (2x + 1)(2x + 1).
- First times first: 2x × 2x = 4x², because 2 × 2 = 4.
- Last times last: 1 × 1 = 1.
- The two middle products are 2x × 1 = 2x and 1 × 2x = 2x. Add their numbers: 2 + 2 = 4.
- So (2x + 1)² = 4x² + 4x + 1.
Answer: 4x² + 4x + 1
See it three ways
With things
Cut a rectangle that is x + 4 long and x + 2 wide into four parts, and add the parts.
As a picture
In words
Multiply every term in the first bracket by every term in the second. That gives four products. Then join the two like terms, 4x and 2x.
In symbols
(x + 4)(x + 2) = x² + 2x + 4x + 8 = x² + 6x + 8.
Try it
Test an expansion with numbers
You need: paper and a pencil.
- Take (x + 3)(x + 2) and its expansion x² + 5x + 6.
- Put x = 1 into both. Work out 4 × 3, and then 1 + 5 + 6.
- Try x = 2, and then x = 10. Write the three results in a table.
What you will see: The brackets and the expansion give the same number every time. If they ever differ, there is a mistake in the expansion.
A wrong idea many people have
(x + 3)² = x² + 9.
Why it feels right: Squaring one number squares it, so it seems that squaring a bracket squares each part inside.
The test that breaks it: Put x = 1. Then (1 + 3)² = 16, but 1² + 9 = 10. They differ, so x² + 9 is wrong.
What is true: A bracket squared is the bracket times itself, with four products. The two middle terms, 3x and 3x, make 6x. So (x + 3)² = x² + 6x + 9.
A wrong idea many people have
(x + 3)(x − 5) = x² − 2x + 15.
Why it feels right: The last term is 3 times 5, so it feels as if it should be a positive 15.
The test that breaks it: Put x = 4. The brackets give 7 × (−1) = −7. But 4² − 2 × 4 + 15 = 23. The two numbers differ.
What is true: The last product is 3 × (−5), and a positive times a negative is negative. It is −15. Always take the sign with the term.
Key words
- expand
- to multiply out brackets, so that no brackets are left.
- term
- one part of an expression that is added or taken away, such as 3x or −15.
- like terms
- terms with the same letters and powers, such as 3x and −5x. They can be joined.
- quadratic expression
- an expression whose highest power of x is x², such as x² + 5x + 6.
Back to your guess
The answer is B: x² + 5x + 6: multiply every term by every term, then join the like terms.
Every term in the first bracket multiplies every term in the second. That gives four products: x², 2x, 3x and 6. The two middle terms are alike and join to make 5x. So (x + 3)(x + 2) = x² + 5x + 6.
Check yourself
Try each one before you look. A wrong answer tells you where to go next.
Expand (x + 4)(x + 3).
See the answer
x² + 7x + 12
The four products are x², 3x, 4x and 12. The two x terms join: 3x + 4x = 7x. So the answer is x² + 7x + 12.
- If you chose A: You multiplied the first terms and the last terms only. Every term in one bracket multiplies every term in the other, so there are four products. Go to M4.9.1.
- If you chose C: You added the terms. The brackets are multiplied, so x × x makes x², not 2x. Go to M4.9.1.
- If you chose D: The 7 and the 12 are the wrong way round. The x terms, 4x and 3x, add to 7x. The last terms multiply: 4 × 3 = 12. Go to M4.9.1.
Expand (x + 2)(x − 6).
See the answer
x² − 4x − 12
The four products are x², −6x, 2x and −12. The x terms join: −6x + 2x = −4x. So the answer is x² − 4x − 12.
- If you chose A: The last product is 2 × (−6). A positive times a negative is negative, so it is −12. Go to M3.1.2.
- If you chose B: The x terms are 2x and −6x. Add the numbers: 2 + (−6) = −4. So the term is −4x, not +4x. Go to M4.9.1.
- If you chose C: You worked out −6 − 2. The x terms are 2x and −6x, and you add them: 2 + (−6) = −4. Go to M4.9.1.
Expand (x − 3)(x − 4).
See the answer
x² − 7x + 12
The four products are x², −4x, −3x and +12. The x terms join: −4x − 3x = −7x. So the answer is x² − 7x + 12.
- If you chose B: The last product is (−3) × (−4). A negative times a negative is positive, so it is +12. Go to M3.1.2.
- If you chose C: The x terms are −3x and −4x. Both are negative, so they add to −7x. Keep the sign with each term. Go to M4.9.1.
- If you chose D: You multiplied only the first terms and the last terms. The two middle products, −4x and −3x, make −7x. Go to M4.9.1.
Expand (3x + 2)².
See the answer
9x² + 12x + 4
The four products are 9x², 6x, 6x and 4. The two middle terms join: 6x + 6x = 12x. So the answer is 9x² + 12x + 4.
- If you chose A: You squared each term and left out the middle term. A bracket squared has four products, and the two middle ones, 3x × 2 and 2 × 3x, make 12x. Go to M4.9.1.
- If you chose B: You found one middle product, 3x × 2 = 6x. There are two of them, 6x and 6x, and together they make 12x. Go to M4.9.1.
- If you chose D: The first term is 3x × 3x. That is 9x², because 3 × 3 = 9, not 3. Go to M4.9.1.
Expand (x − 4)².
See the answer
x² − 8x + 16
The four products are x², −4x, −4x and +16. The two middle terms join: −4x − 4x = −8x. So the answer is x² − 8x + 16.
- If you chose A: You left out the middle term. (x − 4)² is (x − 4)(x − 4), with four products. The two middle products, −4x and −4x, make −8x. Go to M4.9.1.
- If you chose C: You squared each part, x² and (−4)², and dropped the middle term. The middle products are −4x twice, which make −8x. Go to M4.9.1.
- If you chose D: The last product is (−4) × (−4). A negative times a negative is positive, so it is +16. Go to M3.1.2.
Mei expands (x + 5)(x + 2) and gets x² + 7x + 10. To check, she puts x = 1 into both forms. What does she find?
See the answer
Both give 18, so her expansion passes the check.
The brackets give (1 + 5)(1 + 2) = 6 × 3 = 18. The expansion gives 1 + 7 + 10 = 18. The two agree.
Expand (x + 4)(x − 7). The x term is bx. What is b?
See the answer
b = −3
The x terms are 4x and −7x. Add the numbers: 4 + (−7) = −3.
Expand (x + 2)(x + 5) = x² + bx + c. Give b, then c.
See the answer
b = 7, c = 10
The x terms are 2x and 5x, so b = 2 + 5 = 7. The last terms multiply: c = 2 × 5 = 10.
Keep it
Copy this into your exercise book.
Multiply every term by every term. Keep each sign with its term. Join the like terms. A squared bracket is the bracket times itself, with four products. Check with a number.
Draw: A grid with x and +3 across the top, x and −5 down the side, and four products in the cells.