M4.9.1 Chapter 1

Expanding two brackets

I know 3(x + 4) = 3x + 12. What do I do when both parts are brackets, like (x + 3)(x + 2)?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

By the end you can

  • Expand (x + 3)(x − 5)
  • Expand (2x + 1)² without losing the middle term

Amina knows that 3(x + 4) means 3 × x and 3 × 4. The 3 multiplies each part of the bracket. This is called expanding the bracket.

Now take (x + 3)(x + 2). Picture a rectangle that is x + 3 long and x + 2 wide. Its area is the two brackets multiplied together.

A rectangle cut into four parts. The top is marked x + 3 and is cut into x and 3. The left side is cut into x and 2. The four parts hold x², 3x, 2x and 6.x3x2x + 3x²3x2x6
The whole rectangle is made of four parts. Its area is x² + 3x + 2x + 6.

The four parts are the four products. x times x is x². x times 2 is 2x. 3 times x is 3x. 3 times 2 is 6. The parts 3x and 2x are alike, so they join: 5x.

Draw it first

Multiply every pair of terms

  1. A column of expressions with arrows between them. The first is (x + 3)(x + 2). Step 2 adds an arrow with the note multiply every pair of terms, and the expression x² + 2x + 3x + 6. Step 3 adds an arrow with the note join the like terms, and the expression x² + 5x + 6.(x + 3)(x + 2)

    1 Start with the two brackets, (x + 3)(x + 2).

  2. A column of expressions with arrows between them. The first is (x + 3)(x + 2). Step 2 adds an arrow with the note multiply every pair of terms, and the expression x² + 2x + 3x + 6. Step 3 adds an arrow with the note join the like terms, and the expression x² + 5x + 6.(x + 3)(x + 2)(x + 3)(x + 2)x² + 2x + 3x + 6multiply every pair of terms

    2 Multiply every term in the first bracket by every term in the second. There are 2 × 2 = 4 products.

  3. A column of expressions with arrows between them. The first is (x + 3)(x + 2). Step 2 adds an arrow with the note multiply every pair of terms, and the expression x² + 2x + 3x + 6. Step 3 adds an arrow with the note join the like terms, and the expression x² + 5x + 6.(x + 3)(x + 2)(x + 3)(x + 2)x² + 2x + 3x + 6multiply every pair of terms(x + 3)(x + 2)x² + 2x + 3x + 6x² + 5x + 6multiply every pair of termsjoin the like terms

    3 Join the like terms. 2x + 3x = 5x, so the answer is x² + 5x + 6.

A term with a minus sign needs care. A positive number times a negative number is negative. A negative times a negative is positive. Here is a pattern that shows why.

A table with the heads sum and answer. Rows: −5 × 2 gives −10; −5 × 1 gives −5; −5 × 0 gives 0; −5 × −1 gives 5; −5 × −2 gives 10.sumanswer−5 × 2−10−5 × 1−5−5 × 00−5 × −15−5 × −210
Going down the table, the second number falls by 1 each time and the answer rises by 5. So −5 × −1 is 5.

A grid keeps the four products in order. Write one bracket across the top and the other down the side. Each cell holds the product of the terms at the ends of its row and column.

A grid for (x + 3)(x − 5). The terms x and +3 are across the top. The terms x and −5 are down the side. The cells hold x², +3x, −5x and −15. The cells +3x and −5x are hatched, and under the grid is = x² − 2x − 15.x+3x−5x²+3x−5x−15= x² − 2x − 15
The hatched cells are the like terms. Adding them gives 3x − 5x = −2x.

Worked example

Expand (x + 3)(x − 5).

  1. Write the four products: x × x = x², x × (−5) = −5x, 3 × x = 3x and 3 × (−5) = −15.
  2. Add them up: x² − 5x + 3x − 15.
  3. Join the x terms. The numbers in front are −5 and 3, and −5 + 3 = −2.
  4. So the x terms make −2x, and (x + 3)(x − 5) = x² − 2x − 15.

Answer: x² − 2x − 15

You can test an expansion with a number. Put the same value of x into the brackets and into your answer. A right expansion gives the same number both ways.

A table with the heads form and x = 4. Rows: (x + 3)(x − 5) gives −7; x² − 2x − 15 gives −7; x² − 2x + 15 gives 23.formx = 4(x + 3)(x − 5)−7x² − 2x − 15−7x² − 2x + 1523
The first two forms agree. The third gives 23, so it is a wrong expansion.

A bracket squared is the bracket times itself. (2x + 1)² means (2x + 1)(2x + 1). It has four products, not two. The two middle products are equal, and together they make the middle term.

A grid for (2x + 1)². The terms 2x and +1 are across the top and again down the side. The cells hold 4x², +2x, +2x and +1. The cells +2x and +2x are hatched, and under the grid is = 4x² + 4x + 1.2x+12x+14x²+2x+2x+1= 4x² + 4x + 1
The two hatched middle cells are 2x and 2x. They make 4x.

Worked example

Expand (2x + 1)².

  1. Write the square as two brackets: (2x + 1)(2x + 1).
  2. First times first: 2x × 2x = 4x², because 2 × 2 = 4.
  3. Last times last: 1 × 1 = 1.
  4. The two middle products are 2x × 1 = 2x and 1 × 2x = 2x. Add their numbers: 2 + 2 = 4.
  5. So (2x + 1)² = 4x² + 4x + 1.

Answer: 4x² + 4x + 1

See it three ways

With things

Cut a rectangle that is x + 4 long and x + 2 wide into four parts, and add the parts.

As a picture

A rectangle cut into four parts. The top is marked x + 4 and is cut into x and 4. The left side is cut into x and 2. The four parts hold x², 4x, 2x and 8.x4x2x + 4x²4x2x8

In words

Multiply every term in the first bracket by every term in the second. That gives four products. Then join the two like terms, 4x and 2x.

In symbols

(x + 4)(x + 2) = x² + 2x + 4x + 8 = x² + 6x + 8.

Try it

Test an expansion with numbers

You need: paper and a pencil.

  1. Take (x + 3)(x + 2) and its expansion x² + 5x + 6.
  2. Put x = 1 into both. Work out 4 × 3, and then 1 + 5 + 6.
  3. Try x = 2, and then x = 10. Write the three results in a table.

What you will see: The brackets and the expansion give the same number every time. If they ever differ, there is a mistake in the expansion.

If you cannot try it, this is what happens.
A table with the heads x, brackets and expanded. Rows: x = 1 gives 12 and 12; x = 2 gives 20 and 20; x = 10 gives 156 and 156.xbracketsexpanded112122202010156156

A wrong idea many people have

(x + 3)² = x² + 9.

Why it feels right: Squaring one number squares it, so it seems that squaring a bracket squares each part inside.

The test that breaks it: Put x = 1. Then (1 + 3)² = 16, but 1² + 9 = 10. They differ, so x² + 9 is wrong.

What is true: A bracket squared is the bracket times itself, with four products. The two middle terms, 3x and 3x, make 6x. So (x + 3)² = x² + 6x + 9.

A wrong idea many people have

(x + 3)(x − 5) = x² − 2x + 15.

Why it feels right: The last term is 3 times 5, so it feels as if it should be a positive 15.

The test that breaks it: Put x = 4. The brackets give 7 × (−1) = −7. But 4² − 2 × 4 + 15 = 23. The two numbers differ.

What is true: The last product is 3 × (−5), and a positive times a negative is negative. It is −15. Always take the sign with the term.

Key words

expand
to multiply out brackets, so that no brackets are left.
term
one part of an expression that is added or taken away, such as 3x or −15.
like terms
terms with the same letters and powers, such as 3x and −5x. They can be joined.
quadratic expression
an expression whose highest power of x is x², such as x² + 5x + 6.

Back to your guess

The answer is B: x² + 5x + 6: multiply every term by every term, then join the like terms.

Every term in the first bracket multiplies every term in the second. That gives four products: x², 2x, 3x and 6. The two middle terms are alike and join to make 5x. So (x + 3)(x + 2) = x² + 5x + 6.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. Expand (x + 4)(x + 3).

    Tap your answer.
    1. Not this one. You multiplied the first terms and the last terms only. Every term in one bracket multiplies every term in the other, so there are four products. Go to M4.9.1. Try another.

    2. Yes, that is right. The four products are x², 3x, 4x and 12. The two x terms join: 3x + 4x = 7x. So the answer is x² + 7x + 12.

    3. Not this one. You added the terms. The brackets are multiplied, so x × x makes x², not 2x. Go to M4.9.1. Try another.

    4. Not this one. The 7 and the 12 are the wrong way round. The x terms, 4x and 3x, add to 7x. The last terms multiply: 4 × 3 = 12. Go to M4.9.1. Try another.

    See the answer

    x² + 7x + 12

    The four products are x², 3x, 4x and 12. The two x terms join: 3x + 4x = 7x. So the answer is x² + 7x + 12.

    • If you chose A: You multiplied the first terms and the last terms only. Every term in one bracket multiplies every term in the other, so there are four products. Go to M4.9.1.
    • If you chose C: You added the terms. The brackets are multiplied, so x × x makes x², not 2x. Go to M4.9.1.
    • If you chose D: The 7 and the 12 are the wrong way round. The x terms, 4x and 3x, add to 7x. The last terms multiply: 4 × 3 = 12. Go to M4.9.1.
  2. Expand (x + 2)(x − 6).

    Tap your answer.
    1. Not this one. The last product is 2 × (−6). A positive times a negative is negative, so it is −12. Go to M3.1.2. Try another.

    2. Not this one. The x terms are 2x and −6x. Add the numbers: 2 + (−6) = −4. So the term is −4x, not +4x. Go to M4.9.1. Try another.

    3. Not this one. You worked out −6 − 2. The x terms are 2x and −6x, and you add them: 2 + (−6) = −4. Go to M4.9.1. Try another.

    4. Yes, that is right. The four products are x², −6x, 2x and −12. The x terms join: −6x + 2x = −4x. So the answer is x² − 4x − 12.

    See the answer

    x² − 4x − 12

    The four products are x², −6x, 2x and −12. The x terms join: −6x + 2x = −4x. So the answer is x² − 4x − 12.

    • If you chose A: The last product is 2 × (−6). A positive times a negative is negative, so it is −12. Go to M3.1.2.
    • If you chose B: The x terms are 2x and −6x. Add the numbers: 2 + (−6) = −4. So the term is −4x, not +4x. Go to M4.9.1.
    • If you chose C: You worked out −6 − 2. The x terms are 2x and −6x, and you add them: 2 + (−6) = −4. Go to M4.9.1.
  3. Expand (x − 3)(x − 4).

    Tap your answer.
    1. Yes, that is right. The four products are x², −4x, −3x and +12. The x terms join: −4x − 3x = −7x. So the answer is x² − 7x + 12.

    2. Not this one. The last product is (−3) × (−4). A negative times a negative is positive, so it is +12. Go to M3.1.2. Try another.

    3. Not this one. The x terms are −3x and −4x. Both are negative, so they add to −7x. Keep the sign with each term. Go to M4.9.1. Try another.

    4. Not this one. You multiplied only the first terms and the last terms. The two middle products, −4x and −3x, make −7x. Go to M4.9.1. Try another.

    See the answer

    x² − 7x + 12

    The four products are x², −4x, −3x and +12. The x terms join: −4x − 3x = −7x. So the answer is x² − 7x + 12.

    • If you chose B: The last product is (−3) × (−4). A negative times a negative is positive, so it is +12. Go to M3.1.2.
    • If you chose C: The x terms are −3x and −4x. Both are negative, so they add to −7x. Keep the sign with each term. Go to M4.9.1.
    • If you chose D: You multiplied only the first terms and the last terms. The two middle products, −4x and −3x, make −7x. Go to M4.9.1.
  4. Expand (3x + 2)².

    Tap your answer.
    1. Not this one. You squared each term and left out the middle term. A bracket squared has four products, and the two middle ones, 3x × 2 and 2 × 3x, make 12x. Go to M4.9.1. Try another.

    2. Not this one. You found one middle product, 3x × 2 = 6x. There are two of them, 6x and 6x, and together they make 12x. Go to M4.9.1. Try another.

    3. Yes, that is right. The four products are 9x², 6x, 6x and 4. The two middle terms join: 6x + 6x = 12x. So the answer is 9x² + 12x + 4.

    4. Not this one. The first term is 3x × 3x. That is 9x², because 3 × 3 = 9, not 3. Go to M4.9.1. Try another.

    See the answer

    9x² + 12x + 4

    The four products are 9x², 6x, 6x and 4. The two middle terms join: 6x + 6x = 12x. So the answer is 9x² + 12x + 4.

    • If you chose A: You squared each term and left out the middle term. A bracket squared has four products, and the two middle ones, 3x × 2 and 2 × 3x, make 12x. Go to M4.9.1.
    • If you chose B: You found one middle product, 3x × 2 = 6x. There are two of them, 6x and 6x, and together they make 12x. Go to M4.9.1.
    • If you chose D: The first term is 3x × 3x. That is 9x², because 3 × 3 = 9, not 3. Go to M4.9.1.
  5. Expand (x − 4)².

    Tap your answer.
    1. Not this one. You left out the middle term. (x − 4)² is (x − 4)(x − 4), with four products. The two middle products, −4x and −4x, make −8x. Go to M4.9.1. Try another.

    2. Yes, that is right. The four products are x², −4x, −4x and +16. The two middle terms join: −4x − 4x = −8x. So the answer is x² − 8x + 16.

    3. Not this one. You squared each part, x² and (−4)², and dropped the middle term. The middle products are −4x twice, which make −8x. Go to M4.9.1. Try another.

    4. Not this one. The last product is (−4) × (−4). A negative times a negative is positive, so it is +16. Go to M3.1.2. Try another.

    See the answer

    x² − 8x + 16

    The four products are x², −4x, −4x and +16. The two middle terms join: −4x − 4x = −8x. So the answer is x² − 8x + 16.

    • If you chose A: You left out the middle term. (x − 4)² is (x − 4)(x − 4), with four products. The two middle products, −4x and −4x, make −8x. Go to M4.9.1.
    • If you chose C: You squared each part, x² and (−4)², and dropped the middle term. The middle products are −4x twice, which make −8x. Go to M4.9.1.
    • If you chose D: The last product is (−4) × (−4). A negative times a negative is positive, so it is +16. Go to M3.1.2.
  6. Mei expands (x + 5)(x + 2) and gets x² + 7x + 10. To check, she puts x = 1 into both forms. What does she find?

    Tap your answer.
    1. Yes, that is right. The brackets give (1 + 5)(1 + 2) = 6 × 3 = 18. The expansion gives 1 + 7 + 10 = 18. The two agree.

    2. Not this one. Work out the brackets again: (1 + 5)(1 + 2) = 6 × 3 = 18, not 8. Both forms give 18. Go to M4.9.1. Try another.

    3. Not this one. It can. A wrong expansion usually gives a different number. Here both forms give 18, so no mistake shows. Go to M4.9.1. Try another.

    See the answer

    Both give 18, so her expansion passes the check.

    The brackets give (1 + 5)(1 + 2) = 6 × 3 = 18. The expansion gives 1 + 7 + 10 = 18. The two agree.

    • If you chose B: Work out the brackets again: (1 + 5)(1 + 2) = 6 × 3 = 18, not 8. Both forms give 18. Go to M4.9.1.
    • If you chose C: It can. A wrong expansion usually gives a different number. Here both forms give 18, so no mistake shows. Go to M4.9.1.
  7. Expand (x + 4)(x − 7). The x term is bx. What is b?

    See the answer

    b = −3

    The x terms are 4x and −7x. Add the numbers: 4 + (−7) = −3.

  8. Expand (x + 2)(x + 5) = x² + bx + c. Give b, then c.

    See the answer

    b = 7, c = 10

    The x terms are 2x and 5x, so b = 2 + 5 = 7. The last terms multiply: c = 2 × 5 = 10.

Keep it

Copy this into your exercise book.

Multiply every term by every term. Keep each sign with its term. Join the like terms. A squared bracket is the bracket times itself, with four products. Check with a number.

Draw: A grid with x and +3 across the top, x and −5 down the side, and four products in the cells.

Reading with a child? A short page for the adult: what this chapter teaches and three questions to ask.

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