M4.10.5 Chapter 5
Graphs of sin, cos and tan
What does the graph of y = sin x look like, for angles from 0° to 360°?
Your guess
Pick one before you read on. It is fine to be wrong.
By the end you can
- Sketch y = sin x and y = cos x up to 360°
- Use a graph to find two angles with sin x = 0.5
In a right angled triangle, sin of an angle is a ratio of two sides. Here you use sin and cos for any angle from 0° to 360°. Check that your calculator is in degree mode. If sin 30° does not show 0.5, it is not.
Think of a wheel with radius 1. A point P sits on its rim, level with the centre, on the right. Turn the wheel anticlockwise by an angle x. Now P has a height above the centre line, and a distance across from the centre.
We define sin x as the height of P above the centre. We define cos x as its distance to the right of the centre. Below the centre the height is negative. To the left of the centre the distance is negative.
At 30° the point P is at height 0.5, so sin 30° = 0.5. At 150° the point Q is at the same height, so sin 150° = 0.5 too. As the wheel turns, the height of P rises and falls like a wave. Plot it against the angle, and you get the graph of y = sin x.
Worked example
Find sin 210°, using the wheel.
- Work out how far 210° is past the half turn: 210° − 180° = 30°.
- So P is 30° below the horizontal line, on the left. Its distance below the centre is the same as the height at 30°, which is 0.5.
- Below the centre means negative. So sin 210° = −0.5.
Answer: sin 210° = −0.5.
Read the graph from left to right. At 0° it is 0. It rises to 1 at 90° and falls to 0 at 180°. Then it reaches −1 at 270° and is back to 0 at 360°. After 360° the wheel is back where it began, so the wave repeats. The length of one full wave is its period: 360° for sin and cos.
The graph of cos x is the same wave, but it starts at the top. At 0° it is 1. It falls to 0 at 90°, to −1 at 180°, rises to 0 at 270°, and is back at 1 at 360°. Cos x is the distance of P across from the centre, so it starts at 1.
Both waves stay between −1 and 1. So sin x = 2 has no solution at all. The graph of tan x is different. It is sin x divided by cos x. Cos x is 0 at 90° and 270°, so tan x has no value there.
The tan graph passes through 0 at 0°, 180° and 360°. It repeats every 180°, so its period is 180°. At 45° it is 1. Between 90° and 180° it is negative.
Now use the graph to solve an equation. To solve sin x = 0.5, draw the horizontal line y = 0.5 across the sin graph. Each place where it meets the curve gives an angle.
Worked example
Solve sin x = 0.5 for x between 0° and 360°.
- Draw the line y = 0.5 across the graph of y = sin x.
- It meets the curve twice between 0° and 360°.
- The calculator gives the first angle: sin⁻¹ 0.5 = 30°.
- The wave is symmetric about 90°. The second angle is 180° − 30° = 150°.
Answer: x = 30° or x = 150°.
See it three ways
With things
A valve on a bicycle wheel starts level with the centre, on the right, and the wheel turns anticlockwise. At what angles is the valve half a radius above the centre?
As a picture
In words
The valve is at that height twice in one turn. It is there once on the way up, after 30°, and once on the way down, after 150°.
In symbols
sin x = 0.5 gives x = 30° or x = 150°.
Worked example
Solve cos x = 0.5 for x between 0° and 360°.
- The line y = 0.5 meets the cos curve twice between 0° and 360°.
- The calculator gives the first angle: cos⁻¹ 0.5 = 60°.
- The cos wave is symmetric about 180°. From 60° to 180° is 180° − 60° = 120°.
- The second angle is 120° on the other side of 180°: 180° + 120° = 300°.
Answer: x = 60° or x = 300°.
Try it
Measure the sine on a circle
You need: paper, a ruler, a protractor, a pencil.
- Draw a circle with radius 10 cm. Draw a horizontal line through its centre.
- With the protractor, draw radius lines at 30°, 60° and 90° above the horizontal line.
- Measure the height of the end of each radius above the horizontal line. Divide each height by 10.
What you will see: The heights are about 5 cm, 8.7 cm and 10 cm. Divided by 10 they give 0.5, 0.87 and 1. These are sin 30°, sin 60° and sin 90°.
A wrong idea many people have
sin x = 0.5 has only one solution, 30°.
Why it feels right: The calculator gives one answer when you press sin⁻¹, so it seems that there is only one.
The test that breaks it: The wheel point is at height 0.5 at 30°. It is at the same height again at 150°. So sin 150° = 0.5 as well.
What is true: Between 0° and 360° the line y = 0.5 meets the sin wave twice. The calculator gives the first angle. Use symmetry to find the second.
A wrong idea many people have
tan x stays between −1 and 1, like sin x.
Why it feels right: Sin, cos and tan are written alike and come from the same triangle.
The test that breaks it: tan 45° = 1, but tan 80° is about 5.7. The values keep growing as the angle gets close to 90°.
What is true: Only sin x and cos x stay between −1 and 1. The tan graph climbs without limit towards the asymptotes at 90° and 270°.
Key words
- period
- the length of one full wave before the graph repeats. For sin and cos it is 360°.
- sine wave
- the wave shaped graph of y = sin x.
Back to your guess
The answer is B: A wave that rises to 1, falls to −1, and comes back to 0.
The graph of y = sin x is a smooth wave. It starts at 0 and rises to 1 at 90°. It falls through 0 at 180° to −1 at 270°, and is back at 0 at 360°. The wave never goes above 1 or below −1, and it repeats every 360°.
Check yourself
Try each one before you look. A wrong answer tells you where to go next.
The graph shows y = cos x, and a dot at 120°. What is cos 120°?
See the answer
−0.5
Follow the dashed line from the dot across to the y axis: it reaches −0.5. The dot is below the axis, so cos 120° is negative.
A calculator gives sin⁻¹ 0.9 = 64°, to the nearest degree. Which are the two angles between 0° and 360° with sin x = 0.9?
See the answer
64° and 116°
The calculator gives 64°. The sin wave is symmetric about 90°, so the other angle is 180° − 64° = 116°. Check: both angles are 26° from 90°.
- If you chose A: A calculator shows only the first angle. The line y = 0.9 meets the wave twice, once on the way up and once on the way down. Go to M4.10.5.
- If you chose B: That uses the symmetry of the cos wave about 180°. The sin wave is symmetric about 90°. Go to M4.10.5.
- If you chose C: The angle 180° + 64° is below the axis, where sin x is negative. Go to M4.10.5.
Which of these values can sin x never take?
See the answer
1.5
The sin wave stays between −1 and 1. The value 1.5 is above the top of the wave, so no angle has sin x = 1.5.
The graph of y = tan x has an asymptote at one of these angles. Which?
See the answer
90°
Tan x is sin x divided by cos x. At 90° cos x is 0, so the division fails and the graph has an asymptote.
Solve cos x = −0.5 for x between 0° and 360°.
See the answer
x = 120° or x = 240°
The calculator gives cos⁻¹(−0.5) = 120°. The cos wave is symmetric about 180°, so the other angle is 360° − 120° = 240°. Check: 120° and 240° are both 60° from 180°.
- If you chose A: These are the angles for cos x = 0.5. For −0.5 the wave must be below the axis. Go to M4.10.5.
- If you chose B: These two are 30° either side of 180°, where cos x is about −0.87. The value −0.5 comes at 120° and 240°. Go to M4.10.5.
- If you chose C: The cos wave is symmetric about 180°, so the two angles are the same distance either side of 180°. 120° is 60° before 180°, so the other is 60° after it. Go to M4.10.5.
From an earlier chapter
Which of these is a growth curve?
See the answer
y = 6ˣ
A growth curve has a base above 1. Each step multiplies by 6, so the values rise faster and faster.
sin 40° = 0.64, to 2 decimal places. Find the other angle between 0° and 360° with the same sine.
See the answer
140
The sin wave is symmetric about 90°. The other angle is 180° − 40° = 140°.
cos 70° = 0.34, to 2 decimal places. Find the other angle between 0° and 360° with the same cosine.
See the answer
290
The cos wave is symmetric about 180°. The other angle is 360° − 70° = 290°.
Keep it
Copy this into your exercise book.
Sin and cos are waves between −1 and 1, repeating every 360°. Sin starts at 0, cos starts at 1. To solve sin x = 0.5, find 30°, then use symmetry for 150°.
Draw: A sin wave and a dashed cos wave from 0° to 360°. Add a horizontal line at 0.5 that meets the sin wave twice.