S4.12.1 Chapter 1

Charge and current

Amina presses the switch of a torch and the lamp lights at once. What is moving in the wires, and how can we count it?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

  • You picked D. Read on. At the end, the chapter comes back to your guess.

By the end you can

  • Calculate charge from current and time
  • Explain current in metals as a flow of electrons

Press a torch switch and the lamp lights at once, even when the wires are long. So something must already be in the wire, ready to move. That something is electric charge.

Some particles carry charge. An electron carries a negative charge. A metal is made of atoms packed together. Each atom keeps most of its electrons, but one or two are loose. These free electrons wander between the atoms. The rest of each atom is a positive ion, and it stays in its place.

A piece of metal wire drawn side on as a long box. Inside are two rows of six circles with hatching, which are metal ions, and five black dots between the rows, which are electrons. A dashed upright line across the middle of the wire is labelled cross-section. Above the wire an arrow pointing right is labelled conventional current. Below the wire an arrow pointing left is labelled electrons drift. At the foot a key shows a hatched circle as metal ion and a black dot as electron. Labels: conventional current, cross-section, electrons drift, metal ion, electron.conventional currentcross-sectionelectrons driftmetal ionelectron
Inside a metal wire. The ions stay still. The free electrons move. The dashed line is an imagined cut across the wire.

With no cell joined, the free electrons wander in every direction, so nothing flows along the wire. Join a cell, and its push acts on every free electron at once. All of them now drift the same way along the wire. A flow of charge is an electric current.

The drift is slow. In an ordinary copper wire carrying 1 A, the electrons move at well under 1 mm each second. The lamp lights at once because the wire is already full of electrons. The cell pushes one end, and all the electrons start to move together, like beads in a full tube.

To count a current, count the charge that passes. Charge is measured in coulombs, written C. Current is the charge that passes a point each second. It is measured in amperes, called amps for short and written A. A current of 1 A means that 1 C of charge passes each second.

See it three ways

As a picture

A table with the columns Quantity, Symbol and Unit. Row 1: charge, Q, C. Row 2: current, I, A. Row 3: time, t, s.QuantitySymbolUnitchargeQCcurrentIAtimets

In words

Current is the charge that passes each second. A bigger current means more charge each second.

In symbols

I = Q ÷ t. Charge Q is in C, time t is in s and current I is in A. So 1 A = 1 C ÷ 1 s.

A steady current gives the same charge every second. After 2 s, twice as much has passed. After 3 s, three times as much. So a graph of charge against time is a straight line through the origin. Look at a current of 2 A.

Draw it first

Charge against time for a steady current

  1. A graph with the axes charge (C) and time (s). The time runs from 0 to 5 s in steps of 1 and the charge from 0 to 10 C in steps of 2. Step 1: a straight line from the origin to 10 C at 5 s, labelled I = 2 A. Step 2: a dot on the line at 3 s and 6 C, with dashed lines to both axes, labelled 6 C. Step 3: a second dot at 5 s and 10 C, with dashed lines to both axes, labelled 10 C. Labels: charge (C), time (s), I = 2 A, 6 C, 10 C.I = 2 A123452468100time (s)charge (C)

    1 Draw the line. A current of 2 A passes 2 C each second, so the line climbs 2 C for every 1 s.

  2. A graph with the axes charge (C) and time (s). The time runs from 0 to 5 s in steps of 1 and the charge from 0 to 10 C in steps of 2. Step 1: a straight line from the origin to 10 C at 5 s, labelled I = 2 A. Step 2: a dot on the line at 3 s and 6 C, with dashed lines to both axes, labelled 6 C. Step 3: a second dot at 5 s and 10 C, with dashed lines to both axes, labelled 10 C. Labels: charge (C), time (s), I = 2 A, 6 C, 10 C.6 CI = 2 A123452468100time (s)charge (C)

    2 At 3 s the line is at 6 C. The charge is the current times the time: 2 A × 3 s = 6 C.

  3. A graph with the axes charge (C) and time (s). The time runs from 0 to 5 s in steps of 1 and the charge from 0 to 10 C in steps of 2. Step 1: a straight line from the origin to 10 C at 5 s, labelled I = 2 A. Step 2: a dot on the line at 3 s and 6 C, with dashed lines to both axes, labelled 6 C. Step 3: a second dot at 5 s and 10 C, with dashed lines to both axes, labelled 10 C. Labels: charge (C), time (s), I = 2 A, 6 C, 10 C.6 C10 CI = 2 A123452468100time (s)charge (C)

    3 At 5 s the line is at 10 C. The steeper the line, the bigger the current. The gradient of the line is the current.

Turn the equation round to find the charge: Q = It. Charge in coulombs is current in amps times time in seconds. The units agree: A × s = (C ÷ s) × s = C. You can also find the time: t = Q ÷ I.

A loop with a battery of two cells, an ammeter and a lit lamp. Under the ammeter the reading is 0.5 A. Labels: A, 0.5 A.A0.5 A
The lamp loop of the next worked example. The ammeter reads 0.5 A.

Worked example

The ammeter in the loop reads 0.5 A. How much charge passes through the lamp in 20 s?

  1. Write the equation: Q = It.
  2. Put in the numbers: Q = 0.5 A × 20 s.
  3. Q = 10 C.

Answer: 10 C

Worked example

A steady current of 0.4 A flows through a lamp. How long does it take 72 C of charge to pass through it? Give the time in minutes.

  1. We want the time. Turn Q = It round to t = Q ÷ I.
  2. Put in the numbers: t = 72 C ÷ 0.4 A = 180 s.
  3. Change to minutes: 180 s ÷ 60 = 3 min.

Answer: 3 min

Before you put numbers in, change them to the base units: amps and seconds. A milliamp, mA, is one thousandth of an amp, so 1 mA = 0.001 A. A minute is 60 s. Skip this step and the answer is wrong by a factor of 1 000 or 60.

Worked example

A phone charger gives 250 mA for 3 minutes. How much charge passes through it?

  1. Change the current to amps: 250 mA = 250 ÷ 1 000 = 0.25 A.
  2. Change the time to seconds: 3 min = 3 × 60 = 180 s.
  3. Put in the numbers: Q = 0.25 A × 180 s.
  4. Q = 45 C.

Answer: 45 C

How big is a coulomb? One electron carries a charge of only 1.6 × 10⁻¹⁹ C. So 1 C is the charge of about 6.25 × 10¹⁸ electrons. That is about 6 million million million electrons. A small current moves a huge number of them.

Now the direction. Early scientists guessed that current was a flow of positive charge from the + end of a cell round to the − end. Later we found that the moving charges in a metal are electrons, and they go the other way. The old rule stayed. Conventional current is drawn from + round to −. Every rule and equation in this book uses it.

A loop with a battery of two cells on the left, the long plate at the top, marked + at the top and − at the bottom. The label 3 V is beside it. A closed switch labelled switch is on the top wire and a lit lamp labelled lamp is on the right wire. Arrowheads on the wires point clockwise: right along the top and left along the bottom. The word current is in the middle. Labels: 3 V, switch, lamp, +, −, current.+−3 Vswitchlampcurrent
Conventional current leaves the + end of the battery and goes round to the − end.
The same loop with a battery of two cells on the left, marked + at the top and − at the bottom, with the label 3 V. A closed switch labelled switch is on the top wire and a lit lamp labelled lamp is on the right wire. This time the arrowheads on the wires point anticlockwise: left along the top and right along the bottom. The word electrons is in the middle. Labels: 3 V, switch, lamp, +, −, electrons.+−3 Vswitchlampelectrons
The electrons go the other way, from the − end round to the + end. The same loop, the same lamp.

An ammeter measures the current. It goes in the loop, one part after another, which is called being in series. That way all the charge that goes round passes through it.

A loop with a cell, an ammeter A1, a lit lamp and an ammeter A2. Under A1 the reading is 0.3 A. Under A2 the reading is 0.3 A. Labels: A, A1, 0.3 A, A2.A0.3 AA1A0.3 AA2
One ammeter on each side of the lamp. Both read 0.3 A. The lamp does not use up the current.

The current is the same everywhere in a loop with one path. The lamp does not use up charge. What the lamp changes is energy. The cell gives energy to the charges, and the lamp transfers it to its surroundings as heat and light. The next chapter shows how to measure that.

Try it

A tube of peas

You need: a clear plastic tube or a long drinking straw, about 30 cm, dried peas, lentils or small beads that just slide inside it, a thin stick or a pencil.

Be safe: Dried peas and beads are a choking danger. Keep them away from young children, and never put them in the mouth. Do this on a table, and pick up every pea afterwards.

  1. Fill the tube with peas, so that they touch in a row from one end to the other.
  2. Hold the tube level. Push one more pea into the left end with the stick.
  3. Watch the right end. Notice how soon a pea comes out.
  4. Now take out most of the peas and leave only two, far apart. Push one in at the left end and watch again.

What you will see: With a full tube, a pea falls out of the right end at the moment you push at the left. Each pea moved only a little. The push went along the whole row at once. A full wire of free electrons does the same, so the lamp lights at once.

If you cannot try it, this is what happens.
A table with the columns Tube and Far end. Row 1: full, pea out now. Row 2: two peas, pea out later.TubeFar endfullpea out nowtwo peaspea out later

A wrong idea many people have

The lamp uses up the current, so less current comes back to the cell.

Why it feels right: The lamp gives out heat and light, so it seems to take something away. A battery goes flat, so it seems that something is used up.

The test that breaks it: Put an ammeter on each side of the lamp, as in the picture. Both read 0.3 A. If the lamp used up current, the second would read less.

What is true: Current is not used up. The same charge flows out of the lamp as flows in. The lamp changes energy: it takes energy from the charges and gives out heat and light.

A wrong idea many people have

The lamp lights at once because electrons race along the wire at the speed of light.

Why it feels right: Light and electricity both seem instant. Pictures often show an electron dashing round the loop.

The test that breaks it: Work out the drift speed. In a copper wire carrying 1 A, the electrons drift well under 1 mm each second. A 1 m wire would take hours for one electron. The lamp does not wait for that.

What is true: The wire is already full of free electrons. The push of the cell moves all of them together, so the current starts everywhere at once. Each electron drifts slowly.

A wrong idea many people have

Electrons flow from the + end of the cell to the − end, the same way as the arrows in a circuit drawing.

Why it feels right: We draw the current arrow from + to −, and we tend to think the moving things follow the arrow.

The test that breaks it: An electron has a negative charge. Opposite charges attract, so the + end of the cell pulls electrons towards it and the − end pushes them away. Look at the second loop picture.

What is true: Electrons move from the − end round to the + end. The arrows we draw show conventional current, which goes the other way. The maths gives the same answers either way.

Key words

charge
a property of some particles. It makes them feel electric forces. It is measured in coulombs.
electron
a tiny particle with a negative charge. Free electrons in a metal carry the current.
current
the flow of charge. It is the charge that passes a point each second. Its symbol is I.
coulombs
the unit of charge, written C.
amperes
the unit of current, written A. One ampere is one coulomb each second.
conventional current
current drawn from the + end of a cell round to the − end. The electrons go the other way.
ammeter
a meter that measures current. It goes in the loop, in series.
milliamp
one thousandth of an amp, written mA.

Back to your guess

The answer is A: Tiny particles that were already in the wire all start to move together.

A metal wire is full of free electrons. The cell pushes all of them along together, so the lamp lights at once. They drift slowly, and none is used up: the same charge passes every point of the loop each second.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. A steady current of 3 A flows for 5 s. How much charge passes?

    Tap your answer.
    1. Not this one. You added 3 and 5. Charge is the product of current and time: Q = It. Go to S3.10.1. Try another.

    2. Yes, that is right. Q = It = 3 A × 5 s = 15 C.

    3. Not this one. You divided the current by the time. Charge is current times time, not current over time. Go to S3.10.1. Try another.

    4. Not this one. You divided the time by the current. Charge is current times time. Go to S3.10.1. Try another.

    See the answer

    15 C

    Q = It = 3 A × 5 s = 15 C.

    • If you chose A: You added 3 and 5. Charge is the product of current and time: Q = It. Go to S3.10.1.
    • If you chose C: You divided the current by the time. Charge is current times time, not current over time. Go to S3.10.1.
    • If you chose D: You divided the time by the current. Charge is current times time. Go to S3.10.1.
  2. Mei's lamp takes a steady 0.25 A. How long does it take for 30 C of charge to pass through it?

    Tap your answer.
    1. Not this one. You multiplied 30 by 0.25. The time is the charge divided by the current: t = Q ÷ I. Try another.

    2. Not this one. You added the two numbers. Time is charge divided by current. Try another.

    3. Not this one. You divided the current by the charge, the wrong way round. Use t = Q ÷ I. Try another.

    4. Yes, that is right. t = Q ÷ I = 30 C ÷ 0.25 A = 120 s.

    See the answer

    120 s

    t = Q ÷ I = 30 C ÷ 0.25 A = 120 s.

    • If you chose A: You multiplied 30 by 0.25. The time is the charge divided by the current: t = Q ÷ I.
    • If you chose B: You added the two numbers. Time is charge divided by current.
    • If you chose C: You divided the current by the charge, the wrong way round. Use t = Q ÷ I.
  3. A radio takes 400 mA for 5 minutes. How much charge passes through it?

    Tap your answer.
    1. Yes, that is right. 400 mA = 0.4 A and 5 min = 300 s. Q = It = 0.4 A × 300 s = 120 C.

    2. Not this one. You changed the milliamps to amps but forgot to change 5 minutes to 300 s. Try another.

    3. Not this one. You used 400 and 5 as they stand. Change to amps and seconds first: 0.4 A and 300 s. Try another.

    4. Not this one. You changed the minutes to seconds but left the current in mA. 400 mA is 0.4 A. Try another.

    See the answer

    120 C

    400 mA = 0.4 A and 5 min = 300 s. Q = It = 0.4 A × 300 s = 120 C.

    • If you chose B: You changed the milliamps to amps but forgot to change 5 minutes to 300 s.
    • If you chose C: You used 400 and 5 as they stand. Change to amps and seconds first: 0.4 A and 300 s.
    • If you chose D: You changed the minutes to seconds but left the current in mA. 400 mA is 0.4 A.
  4. A cell is joined to a metal wire in a loop. Which way do the electrons in the wire move?

    Tap your answer.
    1. Not this one. That is the way conventional current is drawn. The electrons have a negative charge, so they move the other way. Go to S3.10.1. Try another.

    2. Not this one. With a cell, the push is always the same way, so the electrons drift round the loop in one direction. Try another.

    3. Yes, that is right. Electrons are negative. They are pushed away from the − end and pulled towards the + end. Conventional current is drawn the other way.

    4. Not this one. The electrons do move, slowly. They carry the energy with them as they drift. Try another.

    See the answer

    From the − end of the cell round to the + end

    Electrons are negative. They are pushed away from the − end and pulled towards the + end. Conventional current is drawn the other way.

    • If you chose A: That is the way conventional current is drawn. The electrons have a negative charge, so they move the other way. Go to S3.10.1.
    • If you chose B: With a cell, the push is always the same way, so the electrons drift round the loop in one direction.
    • If you chose D: The electrons do move, slowly. They carry the energy with them as they drift.
  5. Ravi puts an ammeter A1 on one side of a lamp and a second ammeter A2 on the other side. A1 reads 0.2 A. What does A2 read?

    A loop with a battery of two cells, an ammeter A1, a lit lamp and an ammeter A2. Under A1 the reading is 0.2 A. A2 has no reading. Labels: A, A1, 0.2 A, A2.A0.2 AA1AA2
    Tap your answer.
    1. Yes, that is right. There is one path, so the same charge passes every point each second. The current is the same all round the loop, 0.2 A.

    2. Not this one. Current is not used up. The same charge leaves the lamp each second as enters it. Go to S3.10.1. Try another.

    3. Not this one. The charges lose energy in the lamp. The number of charges passing each second stays the same. Try another.

    4. Not this one. A lit lamp has a current through it. The current goes through the lamp and on round the loop. Try another.

    See the answer

    0.2 A

    There is one path, so the same charge passes every point each second. The current is the same all round the loop, 0.2 A.

    • If you chose B: Current is not used up. The same charge leaves the lamp each second as enters it. Go to S3.10.1.
    • If you chose C: The charges lose energy in the lamp. The number of charges passing each second stays the same.
    • If you chose D: A lit lamp has a current through it. The current goes through the lamp and on round the loop.
  6. Why does a lamp light at once when the switch is closed, though the electrons drift very slowly?

    Tap your answer.
    1. Not this one. The drift is slow, well under 1 mm each second. It is the push that starts everywhere at once. Try another.

    2. Not this one. Light does not travel along the wire. The lamp is heated by the current through it. Try another.

    3. Not this one. Charge does move. The free electrons all drift, and they carry energy to the lamp. Try another.

    4. Yes, that is right. Every free electron in the loop starts to drift at the same moment. The current is the same everywhere at once, like peas in a full tube.

    See the answer

    The wire is already full of free electrons, and the push moves them all together

    Every free electron in the loop starts to drift at the same moment. The current is the same everywhere at once, like peas in a full tube.

    • If you chose A: The drift is slow, well under 1 mm each second. It is the push that starts everywhere at once.
    • If you chose B: Light does not travel along the wire. The lamp is heated by the current through it.
    • If you chose C: Charge does move. The free electrons all drift, and they carry energy to the lamp.
  7. The graph shows the charge that has passed a point in a wire as time goes by. The current is steady. What is the current?

    A graph with the axes charge (C) and time (s). The time runs from 0 to 4 s in steps of 1 and the charge from 0 to 10 C in steps of 2. A straight line runs from the origin to 10 C at 4 s. Labels: charge (C), time (s).12342468100time (s)charge (C)
    Tap your answer.
    1. Not this one. You read the charge at the end of the line. The current is the charge each second, which is the gradient. Try another.

    2. Yes, that is right. The line reaches 10 C at 4 s. The current is the gradient, 10 C ÷ 4 s = 2.5 A. Each second 2.5 C passes.

    3. Not this one. You divided the time by the charge. The current is the charge divided by the time. Try another.

    4. Not this one. You read the last time on the axis. The current is the gradient of the line: the charge divided by the time. Try another.

    See the answer

    2.5 A

    The line reaches 10 C at 4 s. The current is the gradient, 10 C ÷ 4 s = 2.5 A. Each second 2.5 C passes.

    • If you chose A: You read the charge at the end of the line. The current is the charge each second, which is the gradient.
    • If you chose C: You divided the time by the charge. The current is the charge divided by the time.
    • If you chose D: You read the last time on the axis. The current is the gradient of the line: the charge divided by the time.
  8. A current of 1.5 A flows for 12 s. Find the charge that passes.

    See the answer

    18 C

    Q = It = 1.5 A × 12 s = 18 C.

  9. A charge of 45 C passes a point in 9 s. Find the current.

    See the answer

    5 A

    I = Q ÷ t = 45 C ÷ 9 s = 5 A.

Keep it

Copy this into your exercise book.

Current is charge each second. I = Q ÷ t, so Q = It. Charge in C, current in A, time in s. Conventional current goes + to −. Electrons go − to +. Current is not used up.

Draw: A loop with a battery, a lamp and an ammeter. Draw the current arrow from + round to −, and a second arrow for the electrons the other way. Write Q = It.

Reading with a child? A short page for the adult: what this chapter teaches and three questions to ask.

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